Find the equation of the tangent to:(1)y=x-2x^2+3 at x=2(2)y=√x+1 at x=4(3)y=x^3-5x at x=1(4)y=4(√x) at (1,4) 相关知识点: 试题来源: 解析 (1)y=-7x+11(2)4y=x+8(3)y=-2x-2(4)y=-2x+6反馈 收藏 ...
题目1.Find the equation of the tangent to the curve y=x2,which is parallel to the x-axis2.Find the equation of the tangent to the curve y=x2-2x which is perpendicular to the line 2y=x-13.Find the equation of the normal to the curve y=3x2-2x-1 whi...
aFind the equation of the tangent to the curve 4x2 + 3y2 = 7 at the point (1,1) . 发现正切的等式对曲线4x2 + 3y2 = 7在点 (1,1) 。[translate]
x=tcos t, y=tsin t; t=π t=π , t=π , and t=π . When t=π, (x,y)=(-π ,0) and (x,y)=(-π ,0), so an equation of the tangent to the curve at the point corresponding to t=π is y-0=π [x-(-π )], or y=π x+π ^2.反馈...
Find an equation of the tangent line to the curve {eq}\tan y + \ln (x+y)=\sin (\frac{\pi}{2}\cos x)+\ln \frac{\pi}{4} {/eq} at the point {eq}(0,\frac{\pi}{4}) {/eq}. Implicit Differentiation: We use the implicit diffe...
Find the equation of the tangent to y = x2+ x + I at the point P on the curve where x = r. 相关知识点: 试题来源: 解析 Differentiating(dy)/(dx)=2x+1 so at P,(dy)/(dx)=2t+1The coordinates f(Parc(t,t^2+t+1)s abc=(2t+1)(x-t)=(tany-(t^2+1)=(-1)^2y=(2t+1...
Answer to: Find the equation of the tangent line and the normal line to the curve (x^2 + y^2)^2 = \frac{25}{3}(x^2 -y^2) at the point (2,-1) By...
Answer to: Find an equation of the tangent line to the curve at the given point. y = (x - 1)/(x - 2) at the point (3, 2). By signing up, you'll get...
百度试题 结果1 题目【题目】Find an equation of the tangent to y= arctanz at the point where x=1 相关知识点: 试题来源: 解析 【解析】y-π/4=1/2(x-1) 反馈 收藏
Tangent line is a line which passes through the curve at only one point. To find the equation of tangent line to any curve,we have to find slope of the line with one point on line. Use point slope form {eq}\displaystyle y-y_1=m(x-...