1【题目】Find an equation for the conic whose graph isshown. 2Find an equation for the conic whose graph is shown.
find the equation of the quadratic relationwith graph.这句话的意思是：找出这个曲线与二次方程式的关系。句中equation表示公式，例如：The equation is simple: research breeds new products.equation of the quadratic表示二次方程。graph表示曲线。这句话是提出了一个要求，那就是找出曲线与二次方程...
Find an equation of the tangent line to the graph of the function at the given point. {eq}f(x)=\ln \frac{5(x+2)}{x}; \ (-\frac{5}{2}, \ 0) {/eq} Equation of the tangent line: To find the equation of the tangent line to ...
find an equation for a line that is normal to the graph of y = xe^x and goes 相关知识点: 试题来源: 解析 找y'x 然后y'x是slope,因为normal垂直perpendicular,所以y1 times y2 equal to -1, then find the value of y2(the normal one), 然后再代入随便一个数到原始y 得出(x,y)坐标,代入...
find the points on the graph of f(x). for x 1 = 1 we have f(1) = 1 3 + 2 = 3 thus, the point is (1,3). for x =−1: f(−1) = (−1) 3 + 2 = 1 thus, the point is (−1,1). step 6: write the equation of the tangent lines. fo...
题的意思是：求f(x)=8/√(x^2+3x)在点(1,4)处的切线方程 重点是求函数在x=1处的f'(x)直接求导很麻烦，可采用对数求导法，lnf(x)=ln8-(ln(x^2+3x))/2 两边同时对x求导，f'(x)/f(x)=-(2x+3)/2(x^2+3x)把x=1,f(x)=4带入，得 f'(x)=-5/2 可以求出切线方程为y...
Answer to: Starting with the graph of y = e^x , find the equation of the graph that results from a. reflecting about the line y=4. b...
Question: Find an equation for f(x) using the tangent function.f(x)= There are 3 steps to solve this one.
百度试题 结果1 题目Find the equation of the quadratic given its graph is: ( is the vertex.) 相关知识点: 试题来源: 解析 y=-2(x-2)^2+3 反馈 收藏
Find an equation of the line that is tangent to the graph of f and parallel to the line g, where f(x) = x^{2}, g=6x-y+9=0. Given k: 2y - 24x + 25 = 0 and the function g(x) = 2x^2 + 12. Find an equation for the line ...