Can you solve this real interview question? Find All Duplicates in an Array - Given an integer array nums of length n where all the integers of nums are in the range [1, n] and each integer appears at most twice, return an array of all the integers that
出现两次的数字必然在数组的长度范围之内,然后用这个数字做索引,数组里面也必然有对应的元素,把它改成负数,因为相同的数字减去1后(因为数组下标从0开始,需要减1,因为1 ≤ a[i] ≤n(n= size of array),减1之后做索引肯定可以索引到数组的元素,也就是有一个参照物了)所对应的索引是一样的,数字出现...
时间复杂度:O(n),空间复杂度:O(n) funcfindDuplicates(nums []int)[]int{len:=len(nums);iflen<=1{returnnil} hashMap :=make(map[int]int) result := []int{}for_, v :=rangenums { _, exist := hashMap[v];if(exist) { result =append(result, v) }else{ hashMap[v] = v } }ret...
LeetCode-442. Find All Duplicates in an Array 文章分类 Given an array of integers, 1 ≤ a[i] ≤n(n= size of array), some elements appeartwiceand others appearonce. Find all the elements that appeartwicein this array. Could you do it without extra space and in O(n) runtime? Exampl...
442. Find All Duplicates in an ArrayMedium Topics Companies Given an integer array nums of length n where all the integers of nums are in the range [1, n] and each integer appears at most twice, return an array of all the integers that appears twice. You must write an algorithm that ...
详见:https://leetcode.com/problems/find-all-duplicates-in-an-array/description/ C++: 方法一: AI检测代码解析 classSolution{public:vector<int>findDuplicates(vector<int>&nums){vector<int>res;for(inti=0;i<nums.size();++i){intidx=abs(nums[i])-1;if(nums[idx]<0){res.push_back(idx+1);...
LeetCode 每日一题 Daily Challenge 637 Average of Levels in Binary Tree 228 -- 2:21 App LeetCode 每日一题 Daily Challenge 24 Swap Nodes in Pairs 156 -- 3:58 App LeetCode 每日一题 Daily Challenge 442 Find All Duplicates in an Array 151 -- 1:37 App LeetCode 每日一题 Daily Challenge...
Solution Code: publicclassSolution{// when find a number i, flip the number at position i-1 to negative.// if the number at position i-1 is already negative, i is the number that occurs twice.publicList<Integer>findDuplicates(int[]nums){List<Integer>res=newArrayList<>();for(inti=0;i...
The array may contain duplicates. *//* MARK: - 题目翻译: 和Find Minimum in Rotated Sorted Array 题目类似 如果 数组中有重复元素怎么办 这会影响运行的时间复杂度吗 假设一个按升序排序的数组在你事先未知的某个旋转点旋转。 (例如: 0 1 2 4 5 6 7 可能变成 4 5 6 7 0 1 2)。
This is a follow up problem to Find Minimum in Rotated Sorted Array. Would allow duplicates affect the run-time complexity? How and why? 描述 假设按照升序排序的数组在预先未知的某个点上进行了旋转。 ( 例如,数组 [0,1,2,4,5,6,7] 可能变为 [4,5,6,7,0,1,2] )。