代码(Python3) class Solution: def findDuplicate(self, nums: List[int]) -> int: # 二分区间左边界,初始化为 1 l: int = 1 # 二分区间右边界,初始化为 n r: int = len(nums) - 1 # 当前区间不为空时,继续二分 while l <= r: # 计算区间中点 mid mid: int = (l + r) >> 1 #...
classSolution:deffindDuplicate(self, nums:List[int]) ->int:# 如果只有两个元素,第一个元素一定是重复元素iflen(nums) ==2:returnnums[0]# fast每次走两步,slow每次走一步,起始点可以为任意位置fast =0slow =0# python没有do while,所以在循环外写了一遍slow = nums[slow] fast = nums[nums[fast]]...
Given an array of integersnumscontainingn + 1integers where each integer is in the range[1, n]inclusive. There is only one duplicate number innums, returnthis duplicate number. Follow-ups: How can we prove that at least one duplicate number must exist innums? Can you solve the problem wi...
You must not modify the array (assume the array is read only). You must use only constant, O(1) extra space. Your runtime complexity should be less thanO(n2). There is only one duplicate number in the array, but it could be repeated more than once 非常好的题目,开始是用二分做的,比...
Python Array Exercises, Practice and Solution: Write a Python program to find the first duplicate element in a given array of integers. Return -1 if there are no such elements.
24. Find Missing Number in an Array of Numbers Between 10 and 20 Write a Python program to find the missing number in a given array of numbers between 10 and 20. Sample Solution-1: Python Code: import array as arr def test(nums): ...
这道题我觉得难点在于C++的代码的编写,用java,python实现可能更快,anyway,看下面的C++代码,用到了hash表,文件名当键,同文件的文件路径当作值,最后筛选出重复的文件加入到结果集合就行了。 代码 class Solution { public: vector<vector<string>> findDuplicate(vector<string>& paths) { ...
0238-product-of-array-except-self.py 0239-sliding-window-maximum.py 0242-valid-anagram.py 0253-meeting-rooms.py 0261-graph-valid-tree.py 0268-missing-number.py 0269-alien-dictionary.py 0271-encode-and-decode-strings.py 0286-walls-and-gates.py 0287-find-the-duplicate-...
对象反序列化时number类型丢失精度如何解决 Array数组的长度上限是多少? 当前ArkTS是否采用类Node.js的异步I/O机制 对于网络请求这I/O密集型任务是否需要使用多线程进行处理 对于@ohos.net.http网络框架是否需要使用TaskPool处理 模块间循环依赖导致运行时未初始化异常问题定位 编译异常,无具体错误日志,难以定...
If you use the Naive method, one performs in a loop and then increases the counter until it reaches the final item on the list, being aware of its number. "O Naive" of Python can be one way to calculate the amount of an array in Python. The Naive method involves creating a block ...