这道题给了我们一个数组,数组中的数字可能出现一次或两次,让我们找出所有出现两次的数字,由于之前做过一道类似的题目Find the Duplicate Number,所以不是完全无从下手。这类问题的一个重要条件就是1 ≤ a[i] ≤ n (n = size of array),不然很难在O(1)空间和O(n)时间内完成。首先来看一种正负替换的方法...
Find the Duplicate Number Given an array nums containing n + 1 integers where each integer is between 1 and n (inclusive), prove that at least one duplicate number must exist. Assume that there is only one duplicate number, find the duplicate one. Note: You must not modify the array (as...
There is only one duplicate number in the array, but it could be repeated more than once. 题目标签:Array, Binary Search, Two Pointers 题目给了我们一个nums array, 让我们找到其中的重复数字。因为这一题有4个条件,所以有难度。1. 要求我们不能改动array;2. 只能用O(1)空间;3. 时间要小于O(n^2...
AC Java: 1publicclassSolution {2publicintfindDuplicate(int[] nums) {3if(nums ==null|| nums.length == 0){4thrownewIllegalArgumentException("Invalid input array.");5}67for(inti = 0; i<nums.length; i++){8intindex =Math.abs(nums[i]);9if(nums[index] > 0){10nums[index] = -nums...
In this Java tutorial, we discussed the two approches to find all duplicate words in aStringand how many number of times they apprear in that String. These Java programs can be used to find the unique words in a string too. Happy Learning !!
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Repeat until all characters in the array have been iterated. Check map.Duplicate charactershave the count of more than 1. Distinct characterswill have the count as 1. 1.2. Java Program publicstaticMap<Character,Integer>getCharBag(Stringinput){Map<Character,Integer>map=newHashMap<>();if(input=...
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in the table. I convert this collection ofArrayLists into a stream on the first line. I filter the stream forArrayLists of length greater than one entry, and I send each suchArrayListtoFilesChecksum, which runs the checksums on all the files in theArrayListand ...
Note: The solution set must not contain duplicate subsets. For example, If nums = [1,2,3], a solution is: [[3],[1],[2],[1,2,3],[1,3],[2,3],[1,2],[]] SubSets 这道题要求 print 出定长 int array 中所有子集合,使用回溯算法遍历定长 array,然后回溯来选择出所有可能的组合. ...