题目链接: Find Duplicate File in System: leetcode.com/problems/f 在系统中查找重复文件: leetcode.cn/problems/fi LeetCode 日更第 248 天,感谢阅读至此的你 欢迎点赞、收藏鼓励支持小满 发布于 2022-09-25 10:08 力扣(LeetCode) Map Python ...
[LeetCode] Find Duplicate File in System 在系统中寻找重复文件 Given a list of directory info including directory path, and all the files with contents in this directory, you need to find out all the groups of duplicate files in the file system in terms of their paths. A group of duplicat...
Description: Given a list of directory info including directory path, and all the files with contents in this directory, you need to find out all the groups of duplicate files in the file system in terms of their paths. A group of duplicate files consists of at least two files that have ...
class Solution: def findDuplicate(self, nums: List[int]) -> int: # 二分区间左边界,初始化为 1 l: int = 1 # 二分区间右边界,初始化为 n r: int = len(nums) - 1 # 当前区间不为空时,继续二分 while l <= r: # 计算区间中点 mid mid: int = (l + r) >> 1 # 统计 nums 中小...
Find the Duplicate Number 参考资料: https://discuss.leetcode.com/topic/64759/very-simple-c-solution https://discuss.leetcode.com/topic/64735/java-simple-solution/2 https://discuss.leetcode.com/topic/64744/2-pass-o-1-space-solution
Leetcode每日一题:287.find-the-duplicate-number(寻找重复数),思路:一开始并没有什么头绪,直接排序加遍历以O(nlgn)的复杂度水过去了,后来看评论才知道有Floyd判圈算法这么秒的方法,简称龟兔赛跑;具体算法讲解可参考文章:算法-floyd判环(圈)算法,讲得很棒,便于理
LeetCode:287. Find the Duplicate Number LeetCode:287. Find the Duplicate Number 找到数组中重复多次的那个数(唯一)。 思路一:元素值作索引 从位置0开始遍历数组,每次得到的元素值作为下一个遍历的元素,并且将遍历过的元素置为0,如果存在重复的元素值,那么这个位置的元素肯定会被多次访问,如果访问到的元素值...
[Leetcode] Find the Duplicate Number 找到重复数字 Find the Duplicate Number Given an array nums containing n + 1 integers where each integer is between 1 and n (inclusive), prove that at least one duplicate number must exist. Assume that there is only one duplicate number, find the ...
LeetCode ・ Open・ May 25, 2020 Find All Duplicates in an Array Editorial 59 82.1K 54 CS_MONK ・ Open・ Mar 25, 2024 Utilizing Integer Range for Duplicate Identification Python C++ Java Python3 307 39K 44 suman mandal ・ Open・ ...
class Solution {public: vector> findDuplicate(vector& paths) { vector> res; unordered_map> m; for(string path:paths){ istringstream is(path); string pre="",t=""; is>>pre; while(is>>t){ int idx=t.find_last_of('('); string dir=pre+"/"+t.substr(0,idx); string content=t.su...