append(f"{directory}/{filename}") # 遍历分组后的文件列表,仅收集内容重复的(文件路径数量大于 1 ) return [ paths for paths in content_to_paths.values() if len(paths) > 1 ] 代码(Go) func findDuplicate(paths []string) [][]string { // contentToPaths 维护文件内容对应的所有文件路径列表 ...
代码如下 classSolution:deffindDuplicate(self, nums:List[int]) ->int:# 如果只有两个元素,第一个元素一定是重复元素iflen(nums) ==2:returnnums[0]# fast每次走两步,slow每次走一步,起始点可以为任意位置fast =0slow =0# python没有do while,所以在循环外写了一遍slow = nums[slow] fast = nums[num...
Sample Solution:Python Code :def find_first_duplicate(nums): num_set = set() no_duplicate = -1 for i in range(len(nums)): if nums[i] in num_set: return nums[i] else: num_set.add(nums[i]) return no_duplicate print(find_first_duplicate([1, 2, 3, 4, 4, 5])) print(find_...
代码(Python3) class Solution: def findDuplicate(self, nums: List[int]) -> int: # 二分区间左边界,初始化为 1 l: int = 1 # 二分区间右边界,初始化为 n r: int = len(nums) - 1 # 当前区间不为空时,继续二分 while l <= r: # 计算区间中点 mid mid: int = (l + r) >> 1 #...
Python代码: class Solution(object): def findDuplicate(self, paths): """ :type paths: List[str] :rtype: List[List[str]] """ filemap = collections.defaultdict(list) for path in paths: roads = path.split() directory, files = roads[0], roads[1:] ...
Scanning characters. Insert a character in the hash table if it’s not present. Otherwise, returning that character as a duplicate. Code Example: #include<iostream>// hashing function object type#include<unordered_set>using namespace std;chargetRepeatingChar(string&str){unordered_set<char>hashObj...
class Solution { public: vector<vector<string>> findDuplicate(vector<string>& paths) { unordered_map<string, vector<string>> m; vector<vector<string>> res; for (string& path : paths) { istringstream is(path); string pre = "", t = ""; is >> pre; while (is >> t) { int idx ...
C program to delete duplicate words in the string C - Sort strings in alphabetical order C - Find frequency of given word in a string C - Find sum of all digits in alphanumeric string C - Copy a string to another string using recursion C - Find first capital letter in a string using...
1239-maximum-length-of-a-concatenated-string-with-unique-characters.py 1299-Replace-Elements-With-Greatest-Element-On-Right-Side.py 1299-replace-elements-with-greatest-element-on-right-side.py 1383-Maximum-Performance-Of-A-Team.py 1383-maximum-performance-of-a-team.py 1448...
The following are two duplicate subtrees: 2 / 4 and 4 Therefore, you need to return above trees’ root in the form of a list. 题目大意 找出一个二叉树中所有的重复子树。重复子树就是一棵子树,在大的二叉树中出现的次数不止一次。 解题方法 ...