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defcount_substring(string,sub_string):count=0ls,lss=len(string),len(sub_string)foriinrange(0,ls-lss+1):ifstring[i:i+lss]==sub_string:count+=1returncount 0
Find a string Somewhat similar but more efficient defcount_substring(string,sub_string):count=0;foriinrange(len(sub_string),len(string)+1):if(string[i-len(sub_string):i]==sub_string):count+=1returncount count_substring():=0foriinrange(0,len(string)):if(string[i:i+len(sub_string)...
Find a string check this def count_substring(string, sub_string): count =0 for i in range(0,len(string)-len(sub_string)+1): try: if string[i:i+len(sub_string)]==sub_string: count+=1 except IndexError: break return count
Find a string Writing one line but hard to undestand code is not considered a good programming practice.You will grasp when you gradually become mastered in Python.However I think writing this type of things only for fun is most suitable....