Can you solve this real interview question? Find the Difference - You are given two strings s and t. String t is generated by random shuffling string s and then add one more letter at a random position. Return the letter that was added to t. Exampl
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Stringtisgenerated by random shufflingstringsand then add one more letter at a random position. Find the letter that was addedint. 字符串s和t由小写字母组成,其中t是通过将s中的字母顺序打乱并在一个随机位置插入某个字母生成的,在找出t中插入的字母。 解: 1、这个字母可能是s中已有的或者是新的字母但...
leetcode卡两个仅由小写字母组成的字符串s和t。字符串t由随机打乱字符串s生成,然后在随机位置再添加一个字母。找到在t中添加的字母。 例子: 输入:s = \"abcd\" t = \"abcde\" 输出:e 解释: 'e'是添加的字母。文件列表 FindDifference-master.zip (预估有个2文件) FindDifference-master findThe...
class Solution { public: char findTheDifference(string s, string t) { vector<int> count(128, 0); for(char ch : s){ count[ch]++; } for(char ch : t){ count[ch]--; } for(char ch = 'a'; ch <= 'z'; ch++){ if(count[ch] != 0){ return ch; } } return ' '; } }...
impl Solution { pub fn find_the_difference(s: String, t: String) -> char { s // 转成字节切片 .as_bytes() // 转成迭代器 .iter() // 串上 t 的字节迭代器 .chain(t.as_bytes().iter()) // 使用 fold 积累 ans ,初始为 0 , // 对每个字符都执行异或操作, // 这样最后的值就是...
When you search for records, you must know the difference between Get and Find. You should also know how to use Find and Next in conjunction. 提示 When using these methods, consider using the partial records methods to improve performance, especially when looping through several re...
不过这里要先将字符“a”转换为 ASCII,才能进行异或运算。 解题代码: ## LeetCode 389E Find the differencefromtypingimportListclassSolution:deffindTheDifference(self,s:str,t:str)->str:c=0## 用 0 和 s 中的每个字母进行异或运算forlins:c=c^ord(l)## ord 转换为 ASCIIprint(c)## 打印中间临时...
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