Find the coordinates of the center of the circle from the equation of a circle {eq}(x + 5) ^ {2} + (y + 7) ^ {2} = 212. {/eq} Circle and its Equation: A circle is a locus of a point that revolves in such a manner so that the ...
Here, the centre of the given circle is at(4,-4). As the circle touches both the axes, its radius is 4 units. The equation of the circle is(x-h)²+(y-k)²=r²or,(x-4)²+{y-(-4)}²=4²or,(x-4)²+(y+4)²=16or,x²-8x+16+y²+8y+16=16or,x²...
1. Find the equation of the circle with(i) Centre at origin and radius 4.(ii) Centre at (-3, -2) and radius 6.(iii) Centre at (2, -3) and radius 5.(iv) Centre at (-3, -3) passing through point(-3,-6) 相关知识点: 试题来源: 解析 (i)x^2+y^2=16(ii)x^2+y^...
百度试题 结果1 题目Find the center and radius of the circle described by the equation. (align*)x^2-2x+y^2-2y=0(align*) 相关知识点: 试题来源: 解析 Center: (align*)(1, 1)(align*) ; Radius: (align*)√2(align*) 反馈 收藏 ...
1Problem 4:Find the equation of the circle tangentto both x-axis and y-axis.The center of the circle is onthe line 5x-3y =8.Problem 4:Find the equation of the circle tangent to both x-axis and y-axis. The center of the circle is on the line 5x-3y =8. 2Problem 4 Find the...
Let the equation of the required circle be .Since the circle passes through points and .Since the centre of the circle lies on line ,From equations (1) and (2), we obtainOn solving equations (3) and (4), we obtain and .On substituting the values of and in equation (1), we obtain...
Find the radius( r) for the circle. The radius is any line segment from the center of the circle to any point on its circumference. In this case, ( r) is the distance between ( (2,7)) and ( (3,4)). ( r=√(10)) ( ((x-h))^2+((y-k))^2=r^2) is the equat...
【题目】一道有关圆的数学题find the equation of the circle whose centre lies on the line 2r + y -1=0 and which passesthrought the points A(-2,0)and B(5,1) 相关知识点: 试题来源: 解析 【解析】圆心在直线2x+y-1=0且过((-2,0)和B(5,1)根据题意圆心还必然在(-2,0)和B(5,1)...
结果1 题目 Q. 3 Find the equation of circle passing through the point of intersection of the lines x + 3y = 0 and 2x -7y =0 whose centre is the point of intersection of lines x+y+1=0 and x-2y+4=0. 相关知识点: 试题来源: 解析 0=-x++ 反馈 收藏 ...
Here, the radius of the circle,r=3 units Since, the circle touches both the axes and completely lies in the third quadrant, its centre is at(-3,-3).Now, the equation of the circle is(x-h)²+(y-k)²=r²or,{x-(-3)}²+{y-(-3)}²=3²or,(x+3)²+(y+3)²...