百度试题 结果1 题目Find the center and radius of the circle described by the equation. (align*)x^2-2x+y^2-2y=0(align*) 相关知识点: 试题来源: 解析 Center: (align*)(1, 1)(align*) ; Radius: (align*)√2(align*) 反馈 收藏 ...
Find the center and radius of the circle with equation (x-4)^2+y^2-16=0. () A. (-4, 0); r= 4 units B. (-4, 0); r= 16 units C. (4, 0); r= 4 units D. (4, 0); r= 16 units 相关知识点: 试题来源: 解析 C ...
Find the center and radius of the circle with the given equation and sketch the circle ( x 1 ) 2 + ( y 2 ) 2 = 16 9 Using the equation, find the center and radius of the circle. Sketch the circle. (x - 1)^2 + (y + 3)^2 = 4 Find the center a...
Find the center and radius of the circle with equation x^2 + y^2 -2x + 4y - 11 = 0. Find the center and the radius of the circle with the equation: x^2 + y^2 + 4x - 6y = 3. Find the center and radius of the circle with equation x^2 +...
To find the center and radius of the circle given by the equation (x+2)2+(y+3)2=5, we will follow these steps: Step 1: Identify the standard form of the circle's equationThe standard form of a circle's equation is:(x−α)2+(y−β)2=r2where (α,β) is the center of ...
百度试题 结果1 题目Find the center and radius of the circle whose equation is (x-2)^2+(y+4)^2=9. 相关知识点: 试题来源: 解析 the circle has center (h,k)=(2,-4) and a radius of 3 units.反馈 收藏
1. Find the equation of the circle with(i) Centre at origin and radius 4.(ii) Centre at (-3, -2) and radius 6.(iii) Centre at (2, -3) and radius 5.(iv) Centre at (-3, -3) passing through point(-3,-6) 相关知识点: 试题来源: 解析 (i)x^2+y^2=16(ii)x^2+y^...
The equation of the circle is given as x2+y2+6x+8y−96=0. Comparing the given equation with general equation of circle, x2+y2+2gx+2fy+c=0 The center of circle is C=(−g,−f) and the radius of circle is r=√g2+f2−c. Therefore, from the given equation, 2g=6,2f...
from Chapter 30/ Lesson 9 39K This lesson focuses on defining a circle, presenting its equation in two different forms (standard and general), and giving examples of how to solve problems. Related to this Question Show that the equation represents a circle, and...
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