Find and simplify the expression if {eq}f(x) = x^{2} - 8 {/eq}. {eq}f(3+h)-f(3) {/eq} Expression: When a relation is defined without any equality or inequality sign, then the relation is called an expression. The simplification of an expression can be found...
Find and simplify an expression for the probability generating function of the random variable xmhrcx-B(4,1/3) 相关知识点: 试题来源: 解析 P(x=x)=(4/x)(2/3)^x(1/3)^x This can be G(t)=(2/3)^4+4(2/3)^5(1/3)^2t+6(2/3)^2(1/3)^2t^2 recognised as a binomial ...
Find and simplify an expression for the probability generating function of the random variable xmhrcx-B(4,1/3) 相关知识点: 试题来源: 解析 P(x=x)=(4/x)(2/3)^x(1/3)^x This can be G(t)=(2/3)^4+4(2/3)^5(1/3)^2t+6(2/3)^2(1/3)^2t^2 recognised as a binomial ...
Find and simplify the expression if f ( x ) = x^2 - 4. f(x + 3 ) Which algebraic expression is equivalent to the expression below? 11(8 + 3x) + 20 Substitute x = 3sec(theta) into the expression ((x^2 - 9)^0.5)/x and simplify as much as possible. ...
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hg[grepl('^MT-',hg)]head(hg)library(stringr)colnames(dat)colnames(dat)=str_split(colnames(dat),'_',simplify=T)[,1]meta=as.data.frame(str_split(colnames(dat),'_',simplify=T)[,1])colnames(meta)=c('cell name')rownames(meta)=colnames(dat)library(Seurat)pbmc<-CreateSeuratObject(count...
解析 Solution:-From the question it is given that a = 5 and b = -3We have,= 2a² + 2ab + 3-ab= 2a² + ab +3Then, substitute the value of a and b in the equation= (2×5²) +(5 × (-3)) + 3= (2×25) +(-15) + 3= 50 - 15+3= 53 - 15=38...
Example question: Evaluate the following one sided limit: Unlike the first function, this one comes with a problem. If you don’t recognize it straight away, look at the graph: Coming from the right, the function doesn’t exist. And therefore, the limit would not exist. However, you can...
Example question: Evaluate the following one sided limit: Unlike the first function, this one comes with a problem. If you don’t recognize it straight away, look at the graph: Coming from the right, the function doesn’t exist. And therefore, the limit would not exist. However, you can...
NCERT solutions for CBSE and other state boards is a key requirement for students. Doubtnut helps with homework, doubts and solutions to all the questions. It has helped students get under AIR 100 in NEET & IIT JEE. Get PDF and video solutions of IIT-JEE Mains & Advanced previous year pap...