Rewrite the function as an equation. ( y=1+(n-1)(-5.7)) Simplify ( 1+(n-1)(-5.7)). ( y=-5.7n+6.7) Choose any value for ( n) that is in the domain to plug into the equation. Choose ( 0) to substitute in for ( n
Find the ordered pair that is a solution to the graphs: y = 2x + 3, y = x - 2. Consider the following function: f(x) = \dfrac{2x + 1}{x - 3}. Find the y-intercept. Find the x-intercepts for graph of the e...
Choose any value forxxthat is in thedomainto plug into theequation. Choose00to substitute in forxxto find theordered pair. Tap for more steps... y=-3+3(0)2 Simplify-3+3(0)2. 3by0. y=-3+02 0by2. y=-3+0 Add-3and0. ...
Choose any value forxxthat is in thedomainto plug into theequation. Choose00to substitute in forxxto find theordered pair. Tap for more steps... y=2(0)+7 Simplify2(0)+7. 2by0. y=0+7 Add0and7. y=7 y=7 Use thexandyvalues to form the. ...
A woman ordered a pair of high-waisted pants in her size online — and was shocked to find they were the entire length of her bodySusanna Heller
Can a composite number be a negative number? If x,y,z are non negative integers, what is the total number of factors of 2^x 3^y 5^z ? How can one determine if an ordered pair is a solution to an equation? How do you convert a number into a percentage?
now r(K), c(K) is a (row, column) pair and the pairs are ordered so that column varies more slowly. But it normally would anyhow. So perhaps what you want is 테마복사 [row, col = find(...); rc = sortrows([row(:), col(:)]); r = rc(:,1); c = rc(:,2); ...
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The equation of a line is linear in two variables, usually x and y, that is satisfied by points of the line. The equation of line is usually found by the point-slope form y - y_1 = m (x - x_1), where m is the slope and (x_1, y_1) is a point on the line.
A k-packing set in G is a selection of vertices, such that the shortest path between each pair of selected vertices has at least k+1 edges. Finding a maximum k-packing set in an arbitrary graph is an NP-hard problem, for any k [2]; nonetheless, some graph classes admit polynomial ...