Answer to: Find an equation for the graph shown below in the form y = Asin(omega x) or y = Acos(omega x) By signing up, you'll get thousands of...
Question: Find an equation for the graph sketched belowf(x)= There are 2 steps to solve this one.
百度试题 结果1 题目Problem, find an equation for each graph.X S-5-6 相关知识点: 试题来源: 解析 y=-3sin(3/2x)-2 反馈 收藏
【题目】Find an equation for the conic whose graph isshown. 答案 【解析】本题需下架 结果二 题目 Find an equation for the conic whose graph is shown. 答案 本题需下架相关推荐 1【题目】Find an equation for the conic whose graph isshown. 2Find an equation for the conic whose graph is sho...
1,4)处的切线方程 重点是求函数在x=1处的f'(x)直接求导很麻烦，可采用对数求导法，lnf(x)=ln8-(ln(x^2+3x))/2 两边同时对x求导，f'(x)/f(x)=-(2x+3)/2(x^2+3x)把x=1,f(x)=4带入，得 f'(x)=-5/2 可以求出切线方程为y-4=-5(x-1)/2 整理得2y+5y-13=0 ...
解答一 举报 在点(3,4/81)求y=4/x^4 对x的偏导d(4x^(-4))/dx=-16x^(-5)把x=3代入,球的直线斜率为-16/243所以equation:y-4/81=-16/243(x-3)同理d(3x^(-4))/dx=-12x^(-5)equation:y-3/625=-12/(5^5) (x-5) 解析看不懂?免费查看同类题视频解析查看解答 ...
Find an equation to the tangent line for the graph of {eq}\displaystyle f {/eq} at the given point. {eq}\displaystyle f(x) = (2x^4 +5)^2 \ \ \ {/eq}; {eq}\displaystyle (-1, 49) {/eq} Equation of a Tangent Line: We will differentiate...
In Exercise, (a) find an equation of the tangent line to the graph of f at the given point, (b) use a graphing utility to graph the function and its tangent line at the point, and (c) use the tangent feature of a graphing utility to confirm your results., 相关知识点: 试题来源...
The vertex form of a quadratic equation is (align*)y = a(x - h)^2 + k(align*) , where (align*)(h, k)(align*) is the vertex of the parabola and (align*)a(align*) is the leading coefficient. Form the given graph, the vertex (align*)(h, k)(align*) of the parabola is ...
Find an equation of the tangent plane to the graph of f(x,y) = 8x^2y+9xy^3 at point (5,12). Find an equation for the tangent plane to the graph of f (x, y) = 5 x y - 3 x^2 - y^2 at the point (2, -2).