百度试题 结果1 题目Find all solutions of equation on the interval [0, 2π].√2 sin θ +1=0 相关知识点: 试题来源: 解析 (5 π )4, (7 π )4
Find all solutions of the equation in the interval [0°, 360°): tanx = 1 Quadrants: The six trigonometric functions are sine , cosine, tangent, cotangent, secant and cosecant. In trigonometry, to find all the solution of the trigonometric functions ...
百度试题 结果1 题目Problem, find all solutions to the equation in the interval [ 0, 2π)sin2x=2sin x 相关知识点: 试题来源: 解析 x=0, π
Find all the solutions to the equation. x^{3/2} = 27 Find the solutions of the equation: 12 x^2 - x = 1. Find all solutions to the equation. 2x^2 + 2x + 5 = 0 Find all solutions of the equation 6 cos 2θ - 3\sqrt{3} = 0. Find all solutions of the equation. \...
Question: In the exercise, find all solutions of the equation in the interval [0, 2π). cos(x+π6)−cos(x−π6)=1 Method to Solve a Trigonometric Equation: In mathematics, we encounter numerous problems involving trigonometr...
解析 Let f(x) denote the left-hand side of the equation . If , then and there are no solutions of the equation. Note that . The solutions of for x<0 are given by , where k is a positive integer. Thus, the solutions of f(x)=0 are , where k is a positive integer. ...
Find all solutions of the equation.(Enter your answer in the form a + bπn,where a[0,2π),b is the smallest possible positive number,and n represents any integer.Round a to four decimal places.)cot(x)=-0.237x=?我输入 arccot(-0.237)+ nπ 是错的…… 答案 题目解方程.(方程的解写...
(1)If x≤−2, the equation is equivalent tox−x−1−−x−2=−2−1+x+2=−2x+1=−2x=−3(2)If −2x+x+1−x−2=−2x−1=−2x=−1(3)If x>−1, the equation is equivalent to2x+1−x−2=−2x−1=−2x=−1So this equation does not h...
Find all whole number solutions of the following equation Ask Question Asked 8 years, 3 months ago Modified 8 years, 3 months ago Viewed 761 times This question shows research effort; it is useful and clear 5 Save this question. Show activity on this post. While training for ...
+⋯=0 . If x ≥q 0, then f(x) ≥q 1 and there are no solutions of the equation. Note that f(-x^2)=1-(x^2)(2 !)+(x^4)(4 !)-(x^6)(6 !)+(x^8)(8 !)-⋯=cos x . The solutions of cos x=0 for x<0 are given by x=π2-π k, where k is a ...