Given an array of integers where 1 ≤ a[i] ≤n(n= size of array), some elements appear twice and others appear once. Find all the elements of [1,n] inclusive that do not appear in this array. Could you do it without extra space and in O(n) runtime? You may assume the returne...
Given an array of integers where 1 ≤ a[i] ≤n(n= size of array), some elements appear twice and others appear once. Find all the elements of [1,n] inclusive that do not appear in this array. Could you do it without extra space and in O(n) runtime? You may assume the returne...
Given an array of integers where 1 ≤ a[i] ≤n(n= size of array), some elements appear twice and others appear once. Find all the elements of [1,n] inclusive that do not appear in this array. Could you do it without extra space and in O(n) runtime? You may assume the returne...
Find all numbers disappeared in an array 448. Find All Numbers Disappeared in an Array Given an array of integers where 1 ≤ a[i] ≤ n (n = size of array), some elements appear twice and others appear once. Find all the el......
LeetCode_448. Find All Numbers Disappeared in an Array,题目描述:思路1:排序后采用双指针法,顺序遍历序列classSolution{public:vector<int>findDisappearedNumbers(vector<int>&nums){inti=1;intn=nums.size();sort(nums.begin(),nums.end
【LeetCode448】Find All Numbers Disappeared in an Array 前者省时间,费空间。后者省空间,费时间。 后者的意思是: nums[i]对应着nums[i]-1这个位置,把这个地方的数字变成相反数,代表这里被占用了。 同时,遍历到该位置时,这里的nums[i]是负数,代表该位置被占用,但是还需要把nums[i]这个数字表征的位置给...
网址:https://leetcode-cn.com/problems/find-all-numbers-disappeared-in-an-array/ 题设:Given an array nums of n integers where nums[i] is in the range [1, n], return an array of all the integers in the range [1, n] that do not appear in nums. ...
def findDisappearedNumbers(self, nums: List[int]) -> List[int]: """Keypoint: how to take a flag at each position""" def way1(): for i, v in enumerate(nums): if nums[abs(v)-1] > 0: nums[abs(v)-1] *= -1 out = list() for i, v in enumerate(nums): if v > 0: ...
简介:LeetCode之Find All Numbers Disappeared in an Array 1、题目 Given an array of integers where 1 ≤ a[i] ≤ n (n = size of array), some elements appear twice and others appear once. Find all the elements of [1, n] inclusive that do not appear in this array. ...
publicList<Integer>findDisappearedNumbers3(int[]nums){List<Integer>list=newArrayList<Integer>();if(nums==null||nums.length<1){returnlist;}for(inti=0;i<nums.length;i++){intval=Math.abs(nums[i])-1;if(nums[val]>0){nums[val]=-nums[val];}}for(inti=0;i<nums.length;i++){if(nums[...