1 Find, algebraically, the set of values of k for which the equation x2-10x+k2=4has real roots.[3] 相关知识点: 试题来源: 解析 x^2-10x+k^2=4 D300rb2-4ac30 (H012-4(1)(K2-4)0 100-4k^2+16≥0 k^2≤29 (k+√(29))(k-√(29))≤0 t-+ 青年 ∴\(k∈D:-√(29)≤k...
(e) Find the domain of {eq}g {/eq}. (f) Find the range of {eq}g {/eq}. Function: Function is a mapping from set A to set B. Domain of the function is the set of values at which the function is defined and ra...
To find the exact solution, we set f(x)=g(x) and solve the resulting equation algebraically.sin x=cos x Equate functionsSince the numbers x for which cos x =0 are not solutions of the equation, we can divide both sides by cos x.(sin x)(cos x)=1 Divide by cos xtan x=1 ...
Find the set of values of m for which the line y = mx + 1 intersects the circle (x - 7)2 + (y - 5)2 = 20 at two distinct points. I understand the question and can find correct values of m for which they are true however can only come to a correct set o...
Domain of a function: Domain of a function is the set of values of independent variable for which the function is defined. In general we can find the the values of independent variable for which either denomenator goes to ...
1. Find derivatives x'(t) and y'(t) algebraically. 2. Write a MATLAB function that calculate derivatives x'(t) and y'(t) numerically with the central finite differences of the second order on the mesh with spacing Explore our homework questions ...
This means that, algebraically, anx-intercept is a point on the graph whereyis zero, and ay-intercept is a point on the graph wherexis zero. More specifically, anx-intercept is a solution to the equation when they-value has been set to zero, and ...
You can usually only find strange behavior like this algebraically, not graphically. Example question 2: What is the limit of f(x) as x approaches 4? Solution:This time, we have a problem, which becomes clear once we draw our green arrows: The top arrow is pointing towards a y-value ...
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As it turns out, this "fake iterative approximation formula" is algebraically related to the near-identity π4+π5≈ e6, as we can see starting with the original formula: x = √((1/√1+π) e3) then changing x to π and removing the square roots: π≈√((1/√1+π) e3) ...