百度试题 结果1 题目Find the nth term of each arithmetic sequence.-|1,-q,-7,-5⋯,forn=|7 相关知识点: 试题来源: 解析 α_n=α_I+ln-I)d a7 = -l · (17 -I)(2)α_(I7)=-|I⋅(I6)(2) α_(I7)=2I 反馈 收藏
百度试题 结果1 题目. In each sequence described, find as.(a)An arithmetic sequence with a_1=1anda_3=25 相关知识点: 试题来源: 解析 (a)a_5=49 反馈 收藏
a_2-a_1=5-(5+k) or -k find the difference between pairs of consecutive termsa_3-a_2=5-k-5 or -k to verify the common difference.The common difference is -k.Add -k to the third term to get the fourth term, and so on.a_4=5-k-k or 5-2ka_5=5-2k-k or 5-3ka_6=...
【题目】Problem 5: In an arithmeic sequence an, a_5=9 ,a_(10)=19 , and 2 -3 is the nth term. Find n. 答案 【解析】Problem 5:Solution: 1 023.We hav a_5=a_1+4d=9anda_(10)=a_1+9d=19Thereforea_1=1 ,d=2a_n=a_1+(n-1)d=2n-1 We know that2^(11)-3=2(2...
百度试题 结果1 题目【题目】T here is an arithmetic sequence below. Find the sum of all the terms in the sequence.2, 5, 8, 11, ,20,23. 相关知识点: 试题来源: 解析 【解析】100. 反馈 收藏
Problem 14: In an arithmetic sequence an, if a_3a_7=-16 , a_4+a_6=0 , find Sn, the sum of first n terms. 相关知识点: 试题来源: 解析 Problem 14: Solution: n(n-9)or-n(n-9). Let the common difference of the arithmetic se- quence an be d \(a_1+2d=(a_1+6d)=...
百度试题 结果1 题目Find the sum of the arithmetic sequence.∑_(i=1)^∑(2i-3) 相关知识点: 试题来源: 解析 =3601a_1=2(1)-3=-1 a_(20)=2(20)-3=37 20 反馈 收藏
【题目】T hree consecutive terms in an arithmetic sequence are 3e p, 5, 3e^pFind the possible values of p. Give your answers in an exact form. 答案 【解析】T he vale of p i n3 o n3相关推荐 1【题目】T hree consecutive terms in an arithmetic sequence are 3e p, 5, 3e^pFind the...
结果一 题目 【题目】Given an arithmetic sequence: 5, 10, 15, ., 30, 35, find the total number of terms in this sequence. 答案 【解析】7.相关推荐 1【题目】Given an arithmetic sequence: 5, 10, 15, ., 30, 35, find the total number of terms in this sequence....
(2) The differences between any two adjacent terms form an arithmetic sequence, so, the 101th term is 1+2+3+4+…+100=5051.结果一 题目 【题目】(1)Find the pattern in the sequence and calculate the sum.1,3,4,6,7,9,10,12,13,···,39,40.(2)Find the 101t hterm in the seque...