#include <tbb/task_scheduler_init.h>#include<tbb/blocked_range.h>#include<tbb/parallel_reduce.h>#include<tbb/tick_count.h>#include<stdio.h>usingnamespacestd;usingnamespacetbb;//! Matrix 2x2 classstructMatrix2x2 {//! Array of unsigned intsunsignedintv[2][2]; Matrix2x2() {} Matrix2x...
// without Recursion #include <iostream> using namespace std; int main() { int n1=0,n2=1,n3,i,number; cout<<"Enter the number of elements: "; cin>>number; cout<<n1<<" "<<n2<<" "; //printing 0 and 1 for(i=2;i<number;++i) //loop starts from 2 because 0 and 1 are ...
for (i=1;i<=10;i++) { printf("%5ld %5ld",f1,f2); f1=f1+f2; f2=f2+f1; } printf("\n"); } *8. Write a program to output the Multiplication Table(乘法表)using the nested loop. Referrence program #include main() { int i,j; for(i=1;i<=9;i++) for(j=1;j<=i;j...
{ public: bool isPalindrome(int x) { string s = to_string(x); for(int i=0; i
#include<iostream> #include<vector> using namespace std; vector<int> a; void init() { a....
Execute report you can find out that the second approach to calculate using ABAP internal table is greatly faster than the first solution. Christian Drumm has also provided another approach in his blog Functional ABAP – Functional Programming in ABAP ?! The approach to simulate next call is als...
Twitter Google Share on Facebook Fibonacci Dictionary Wikipedia Related to Fibonacci:Leonardo Fibonacci Fibonacci NationalityItalian Known forFibonacci number. Introduction of digital notation to Europe Leonardo, also calledLeonardo of Pisa. ?1170--?1250, Italian mathematician: popularized the decimal system...
#include <iostream>usingnamespacestd;intfibonacci(intfib) {if(fib==0)return0;if(fib==1||fib==2){return1; }else{returnfibonacci(fib-1)+fibonacci(fib-2); } }intmain() {intn; cin>>n;for(inti=1;i<=n;i++){ cout<<fibonacci(i)<<" "; }return0; } ...
fun fibonacciUsingIteration(num: Int): Int { var a = 0 var b = 1 var tmp: Int for (i in 2..num) { tmp = a + b a = b b = tmp } return b } In this approach, we are using a loop instead of the recursion. Thanks to that, it’s more efficient for larger values. Let...
设斐波那契数列模 $p$ 时的循环节长度为 $loop(p)$,$10^9 = 2^9 \cdot 5^9$,易知 $loop(512)=768$,$loop(1953125)=7812500$。 模数只拆成了两部分,甚至不用上中国剩余定理的模板。 #include<bits/stdc++.h> using namespace std; typedef long long ll; ...