这个数列从第3项开始,每一项都等于前两项之和。 根据以上定义,用python定义一个函数,用于计算斐波那契数列中第n项的数字是多少: deffib_recur(n):ifn==0:return""elifn==1orn==2:return1else:return(fib_recur(n-1) + fib_recur(n-2))#每一项返回的结果都是前两项之和 调用这个函数试一下: print(...
Above function uses recursion to calculate the nth number in theFibonacci sequenceby summing the previous two numbers. Fibonacci series using Dynamic Programming Following is an example of a function to generate theFibonacci seriesusing dynamic programming in Python: def fibonacci(n): if n <= 1: ...
17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 lis=[] deffib(depth): # if depth==0: # a1=0 # a2=1 # a3=a1+a2 # elif depth==1: # a1=1 # a2=1 # a3=a1+a2 # else: # fib(depth)= fib(depth-2) + fib(depth-1) ...
3个函数的执行速度...fibo1:267914296:67.31945824623108 fibo2:267914296:0.0 fibo3:267914296:0.0 由于第一个函数运行速度非常慢,在n变大时只测试后面2个函数的执行时间...0.0 当n=380时,第二个函数由于递归深度过大而崩溃,抛出异常: RecursionError: maximum recursion depth exceeded while calling a Python...
#include<stdio.h>#include//递归计算斐波那契数longfib_recursion(intn){if(n<=2){return1;}else{returnfib_recursion(n-1)+fib_recursion(n-2);}}//迭代计算斐波那契数longfib_iteration(intn){longresult;longprevious_result;longnext_older_result;result=previous_result=1;while(n>2){n-=1;next_old...
RecursionError: maximum recursion depth exceeded while calling aPythonobject 下面继续测试第3个函数,当n=500时,运行结果为: fibo3:139423224561697880139724382870407283950070256587697307264108962948325571622863290691557658876222521294125:0.015594482421875 当n=1000时,运行结果为:fibo3:434665576869374564356885276750406258025646605173717804024...
1）第⼀次写程序的Python程序员：def fib(n):return nth fibonacci number 说明：第⼀次写程序的⼈往往遵循⼈类语⾔的语法⽽不是编程语⾔的语法，就拿我⼀个编程很猛的哥们来说，他写的第⼀个判断闰年的程序，⾥⾯直接是这么写的：如果year是闰年，输出year是闰年，否则year不是闰年。2）刚...
RecursionError:maximum recursion depth exceededwhilecalling a Pythonobject下面继续测试第3个函数,当n=500时,运行结果为: fibo3:139423224561697880139724382870407283950070256587697307264108962948325571622863290691557658876222521294125:0.015594482421875当n=1000时,运行结果为:fibo3:43466557686937456435688527675040625802564660517371780402481729089...
递归Recursion——Fibonacci 题目是构建一个Fibonacci数列 这是原来自己写的代码: k = int(input("Which term? ")) #输入要寻找的数 count = 2 # 计数 next_num = 0 #原始的Fibonacci函数里的数 if int(k) <= 2: #当数是F1和F2的时候就直接print1 print(1) el... ...
Write a Python program to generate the Fibonacci sequence up to 50 using a while loop. Write a Python program to use recursion to print all Fibonacci numbers less than 50. Write a Python program to build the Fibonacci series up to a given limit and store the result in a list. ...