'This inner function takes three arguments and returns a Fibonacci series'The three arguments are nth Fibonacci value, the initial array and a sequence array (sequential numbers from 1 to n)'Note, the sequence array can instead be generated inside the function but it may inefficient=Lambda(NthF...
I tested it for FIBO(SEQUENCE(10000)) and in the worst-case scenario, it took 20ms, so it serves to get a single Fibonacci number or a series.Short, no recursive, and low computation effort. It reminds me of this heuristic rule that I heard once, :-): T+S+H=C Thinking (T) pl...
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'This inner function takes three arguments and returns a Fibonacci series'The three arguments are nth Fibonacci value, the initial array and a sequence array (sequential numbers from 1 to n)'Note, the sequence array can instead be generated inside the function but it may inefficient=Lambda(NthF...
LET( Fᵣ, Fᵣ₋₁ + Fᵣ₋₂, seq, IF(r<n₀, FIB(r+1,n₀,Fᵣ,Fᵣ₋₁), 0), IF(r=SEQUENCE(n₀), Fᵣ, seq) ) )(2,8,0,1) To save the user from needing to initialise the recursion, I have used a wrapper function ...
=Lambda(n,\n\tLet(\n\t\tSqn,sequence(n),\n\t\tinitval,sign(Sqn-1),\n\t\tNthfib,Infib(n,0,1),\n\t\tInFibser(Nthfib, Initval, Sqn)\n\t)\n )This final function can be used by the user to generate the Fibonacci series by merely passing the number of values required ...
Seed,SEQUENCE(1,1,n,0), Iterate,LAMBDA(ME,Seed, LET(PriorVal,NUMBERVALUE(ARRAYTOTEXT(INDEX(Seed,ROWS(Seed))), CurrVal,Next(PriorVal), CurrResult,IF(SEQUENCE(ROWS(Seed)+1)<(ROWS(Seed)+1),Seed,CurrVal), IF(PriorVal=1,Seed,IF(CurrVal=1,CurrResult,ME(ME,CurrResult))) ) ), Iterate...
SEQUENCE(n,,0), LET(b,FIB(n-1), IF(SEQUENCE(n)<n,b,INDEX(b,n-1)+INDEX(b,n-2)) ))) it returns errors message as expected for FIB(10.1), but the spill as for FIB(10+1e-14). Correction could be =LAMBDA(n, IF(n<>INT(n),"use integer as argument", LET...
Seed,SEQUENCE(1,1,n,0), Iterate,LAMBDA(ME,Seed, LET(PriorVal,NUMBERVALUE(ARRAYTOTEXT(INDEX(Seed,ROWS(Seed))), CurrVal,Next(PriorVal), CurrResult,IF(SEQUENCE(ROWS(Seed)+1)<(ROWS(Seed)+1),Seed,CurrVal), IF(PriorVal=1,Seed,IF(CurrVal=1,CurrResult,ME(ME,CurrResult))) ) ), Iterate...
calculation until the entire recursion is expanded up to the end n=2. On each call of the recursion, only the last row changes from the previous one, adding the next Fibonacci number. It is ensured by the second IF condition until it goes to the last one which is the sequence: {1;1...