package第八次模拟;importjava.util.Scanner;publicclassDemo12Fibonacci{publicstaticvoidmain(String[] args){Scannersc=newScanner(System.in);while(sc.hasNext()){intn=sc.nextInt();int[]f =newint[n+2];int[] count=newint[n+2]; f[1]=1; f[2]=1;for(inti=3; i <=n; i++) { f[i]...
publicclassForeachForFibonacciSequence {publicstaticvoidmain(String[] args) { System.out.println(foreach(100)); }publicstaticdoubleforeach(doublei) {if(i <=0d) {return0d; }if(i ==1d) {return1d; }doubletemp1 =0d;doubletemp2 =1d;doubletempSum = 0;for(doubled = 2; d <= i; d++...
AI代码解释 intFibonacci_2(int n){if(n==1||n==2)return1;int f1=1;int fs2=1;for(int i=3;i<=n;i++){int tmp=f1+f2;f1=f2;f2=tmp;}returnf2;} 使用三个辅助变量进行迭代,时间复杂度O(n),但是空间复杂度降为O(1)。 三、斐波那契数列与黄金分割数 随着n趋向无穷大,斐波那契数列中前一项...
AI代码解释 importjava.io.*;importjava.util.*;importjava.math.*;publicclassFibonacci{// Returns n-th Fibonacci numberstaticBigIntegerfib(int n){BigInteger a=BigInteger.valueOf(0);BigInteger b=BigInteger.valueOf(1);BigInteger c=BigInteger.valueOf(1);for(int j=2;j<=n;j++){c=a.add(b);a...
Run Code Output Fibonacci Series till 10 terms: 0, 1, 1, 2, 3, 5, 8, 13, 21, 34, In the above program, firstTerm and secondTerm are initialized with 0 and 1 respectively (first two digits of Fibonacci series). Here, we have used the for loop to print the firstTerm of the ...
importjava.util.Scanner; publicclassMain{ publicstaticvoidmain(String[]args) { int[]a=newint[10000001]; a[1]=1; a[2]=1; intn=newScanner(System.in).nextInt(); for(inti=3;i<=n;i++){ a[i]=(a[i-1]+a[i-2])%10007; ...
The recursion is straightforward from the code perspective, but it’s expensive from a complexity point of view. 3. Iterative Approach Now, let’s have a look at the iterative approach: fun fibonacciUsingIteration(num: Int): Int { var a = 0 var b = 1 var tmp: Int for (i in 2.....
JGShining | We have carefully selected several similar problems for you: 1061 1108 1071 1049 1032 Acceptet Code //通过对各项除3取余发现每8项是一个循环 package cn.edu.hdu.acm; import java.util.Scanner; public class Main1021 { public static int fib(int n) { n = n % 8; if (n =...
void Fib(int x) { ans1 = ans2 = ans3 = 1; for(int i = 3; i <= x; i++) { ans3 = (ans1 + ans2)%10007; ans1 = ans2; ans2 = ans3; } } 1. 2. 3. 4. 5. 6. 7. 8. 9. 10. 11. View Code 后来看了看别人的代码,发现还是用了数组来储存数据,同时还用到了同余...
Write a Java recursive method to calculate the nth Fibonacci number. Sample Solution: Java Code: publicclassFibonacciCalculator{publicstaticintcalculateFibonacci(intn){// Base case: Fibonacci numbers at positions 0 and 1 are 0 and 1, respectivelyif(n==0){return0;}elseif(n==1){return1;}//...