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sites", $connection); $result = mysql_query ("SELECT * FROM sites", $connection); while ($row = mysql_fetch_array($result, MYSQL_NUM)) { foreach ($row as $attribute) print "{$attribute[1]} "; }现在看看 CI 如何处理同一个问题: 复制代码到剪贴板PHP 代码$this->load->database('...
I am fetching mysql data with node js, with making connection with node js to mysql. I am feeling very happy to share this code because it helped me and I hope, It will help others. Here is the working data picture: For Install mysql package into your node js app, need to run belo...
Experience working with Laravel, CodeIgniter, or other PHP Frameworks Experience with SQL server database technologies. Experience with jQuery and Javascript Preferred: Two years of professional web development experience. Experience with Wordpress Templates ...
感谢我的答案,我发现我无法使用fetch_all()因为我使用PHP 5.2.17–fetch_assocwhile循环工作。 我正在使用fetch_all的函数返回这个错误: 致命错误:调用未定义的方法mysqli_result :: fetch_all()中 $mysqli = new mysqli($host, $username, $password, $database); $query = "LONG QUERY that works, test...