题目链接 CF754D Fedor and coupons CF1029C Maximal Intersection 后者是前者的加强版。 思路分析 最开始,先考虑不删区间(k=0)的情况: 也就是给你一大堆区间,让你找他们的交集。 这个还是比较好想的,我们刚开始让第二个区间与第一个区间相交,得到的是一个以max(l1,l2)为左端点,以min(r1,r2)为右端点的...
CodeForces 754D Fedor and coupons (优先队列) 目录作者:@dwtfukgv本文为作者原创,转载请注明出处:https://www.cnblogs.com/dwtfukgv/p/6287343.html题意:给定n个优惠券,每张都有一定的优惠区间,然后要选k张,保证k张共同的优惠区间最大。析:先把所有的优惠券按左端点排序,然后维护一个容量为k的优先队列,...
kcoupons in such a way that the number of such productsxthat all coupons can be used with this productx Input nandk(1 ≤ k ≤ n ≤ 3·105) — the number of coupons Fedor has, and the number of coupons he wants to choose. nlines contains two integersliandri(9 ≤...
Codeforces-754D Fedor and coupons 2017-09-22 21:40 −... xFANx 0 177 CodeForces-1278B-A-and-B 2019-12-20 11:50 −**题意** 对于$t(1\leq t\leq 100)$个测试点,给两个数$a$和$b$,作如下操作: 第一次挑一个数使其加$1$,第二次挑一个数使其加$2$,以此类推,最后两个数相等...
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还记得lyf说过k=2的方法,但是推广到k是其他的话有点麻烦。现在这里采取另外一种方法。 先将所有线段按照L进行排序,然后优先队列保存R的值,然后每次用最小的R值,和当前的L来维护答案即可。同时,如果Q的size()比k大,那么就弹出最小的R。 具体见代码: 另外,输出方案的
cf-754 D Fedor and coupons(优先队列+区间贪心) https://codeforces.com/problemset/problem/754/D 题意: 给定n组区间,要求选出k组区间保证其交集最大,并输出选出的区间 思路: 区间贪心,优先队列算一下天数即可。 代码: #include<iostream>#include<stdio.h>#include<stdlib.h>#include<string>#include<...
D. Fedor and coupons 二分暴力 http://codeforces.com/contest/754/problem/D 给出n条线段,选出k条,使得他们的公共部分长度最大。 公共部分的长度,可以二分出来,为val。那么怎么判断有k条线段有共同的这个长度,而且选他们出来呢? 可以把右端点减去val - 1,那么以后就只需要k条线段至少有一个交点就可以了...
D. Fedor and coupons time limit per test 4 seconds memory limit per test 256 megabytes input standard input output standard output All our characters have hobbies. The same is true for Fedor. He enjoys shopping in the neighboring supermarket. ...
The first line contains two integersnandk(1 ≤ k ≤ n ≤ 3·105) — the number of coupons Fedor has, and the number of coupons he wants to choose. Each of the nextnlines contains two integersliandri( - 109 ≤ li ≤ ri ≤ 109) — the description of...