(2)Solution:Using the splitting the middle term method,We have to find a number whose sum=7 andproduct=2× 3=6We get 6 and 1 as the numbers [6+1=7 and6× 1=6]2x2+7x+3=2x2+6x+1x+3=2x(x+3)+1(x+3)=(2x+1)(x+3)(3)Solution:Using the splitting the middle ...
⑴分解因式:x4+2x3+3x2+2x+1;⑵分解因式:x4+7x3+14x2+7x+1;⑶分解因式:x4+y4+(x+y)4. 答案 ⑴法一:原式=x4+2x3+3x2+2x+1=x4+2x3+x2+2x2+2x+1=(x2+x)2+2(x2+x)+1=(x2+x+1)2;法二:原式=(x4+1)+2x(x2+1)+3x2=(x2+1)2−2x2+2x(x2+1)+3x2=...