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(i) x^(2)+9x+18=x^(2)+6x+3x+18 {by splitting middle term] =x(x+6)+3(x+6)=)x+3(x+6) (ii) 6x^(2)+7x-3=6x^(2)+9x-2x-3 [by splitting middle term] (iii) 2x^(2) -7x -15=2x^(2) -10x+3x-15 [by splitting middle term] =2x(x-5)+3(x-5)=(2x+3)(x-5)
–9x + 2x – 18 = x(x – 9) + 2(x – 9) = (x – 9)(x + 2) hence, the required factors are: (x-9)(x+2) test your knowledge on factoring polynomials q 5 put your understanding of this concept to test by answering a few mcqs. click ‘start quiz’ to begin! select ...
x^{2} -5x - 6 Factorize the polynomial. 5x^{2}-13x-6 Factorize the polynomial. x^{2} - 9x - 1 Completely factorize the polynomial: z^2 + 2z + 3 Factorize the polynomial. x^{2} + 9x + 20 Factorize the polynomial. 3a^{2}-10a+8 Factorize the polynomial. x^{2}...
百度试题 结果1 题目(b) Factorise fully 6x^3-27x^2+30x=3x(2x2-9x+10) [M1]=3x(2x-5)(x-2) 相关知识点: 试题来源: 解析 =3x(2x²-9x+10) [M1] = 3x(2x-5)(x-2) 反馈 收藏
Step by step video, text & image solution for Factorise : 9x^(2) + 3x - 8y - 64y^(2) by Maths experts to help you in doubts & scoring excellent marks in Class 9 exams. Updated on:21/07/2023 Class 9MATHSPOLYNOMIALS Topper's Solved these Questions ...
Factorise : x^(2) + 4y^(2) + 25z^(2) - 4xy + 20 yz - 10 zx 04:14 Factories : 121x^(2) -2 89 01:30 Factorise : (9)/(25)x^(2) - (3)/(5)xy + (1)/(4)y^(2) 02:38 Factorise : 9x^(2) + 25y^(2) + 49z^(2) - 30xy - 70 yz + 42 zx 04:26 Factori...
(i)2x3−9x2+12x−(9/2)=0 (ii)2x3−9x2+12x−3=0 View Solution Free Ncert Solutions English Medium NCERT Solutions NCERT Solutions for Class 12 English Medium NCERT Solutions for Class 11 English Medium NCERT Solutions for Class 10 English Medium ...
View Solution Factorize each of the following expressions:9x2−4y2(ii)36x2−12x+1−25y2 View Solution Free Ncert Solutions English Medium NCERT Solutions NCERT Solutions for Class 12 English Medium NCERT Solutions for Class 11 English Medium ...