Factorise x3−2x2−x+2 01:28View Solution Factorise : x^(2)-y^(2)-2x+1 02:16View Solution Factorise x3+2x2+x. 01:10View Solution Factorise x2+a2+2a+2x+2ax. 01:45View Solution Factorise : a2x2+(ax2+1)x+a 02:10View Solution x2−11x−80 Factorise 02:48View Solution...
Factorise :x3+13x2+31x−45. 01:43 View Solution Factorise the following : x2−14x+45 01:36 View Solution Exams IIT JEE NEET UP Board Bihar Board CBSE Free Textbook Solutions KC Sinha Solutions for Maths Cengage Solutions for Maths ...
解答:提取公因式2,得到$2(x^2 - 2x + 1)$。然后利用完全平方公式,得到$2(x - 1)^2$。 将多项式$x^2 + 4x - 5$进行因式分解。 解答:利用十字相乘法,找到两个数-1和5,它们的和等于4,它们的积等于-5。然后将其与多项式的一次项和常数项组合,得到$(x - 1)(x + 5)$。...
【题目】Questions that require solutions(1)Factorise:3ax+4by+4ay+3bx .(2)Factorise:x^2-2xy-a^2+y^2 (3)Factorise:7x^2-3y+xy-21x .(4)Factorise:4a^2-4(ab+4)+b^2 .(5)Factorise:x^2-4xy+4y^2-2x+4y-3 .(6)Factorise:a^2-a^2b+ab^2-a+b-b^2. ...
such that a + b =5 and ab = 6. on solving this we obtain, a = 3 and b = 2 thus, the above expression can be written as: x 2 + 3x + 2x + 6 = x(x + 3) + 2(x + 3) = (x + 3)(x + 2) thus, x+3 and x+2 are the factors of the polynomial x 2 + 5x + ...
百度试题 结果1 题目Factorise x2−2x−63. 因式分解x2−2x−63.相关知识点: 试题来源: 解析 (x+7)(x−9). x2−2x−63 =x2+(7−9)x+(7)×(−9) =(x+7)(x−9).反馈 收藏
百度试题 结果1 题目Factorise2x^2+3x-5(2x+5)(x-1) 相关知识点: 试题来源: 解析 (2x+5)(x-1) 反馈 收藏
Considering theways of obtaining –3 gives:2x²-x-3 = (2x )(x )-1 +3+1-3 Note that these will+3-1 be multiplied by the-3+1 2 in the 2x termFrom the last of these we can obtain the middle middle term,(-3×x)+(1×2x) =-3x+2x=-xso2x²-x-3 = (2x-3)(x+1)....
百度试题 结果1 题目Factorise2x^2+17x+21(2x+3)(x+7) 相关知识点: 试题来源: 解析 (2x+3)(x+7) 反馈 收藏
题目 9. (a) Factorise 2x^2-x-10(2x-5)(x+2)...(2)(b) Solve 2x^2-x-10=02x*5=0⇒x=5/2 x+2=0⇒x=-2 ■■(1) 相关知识点: 试题来源: 解析(2x - 5)(x + 2)2x × 5 = 0 → x = 5/2x + 2 = 0 ⇒ x = -2 反馈...