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x2+(7+p)x+(6+6p) Step 2: Identify the quadratic formNow, we can see that the expression is in the form of a quadratic equation:x2+(7+p)x+(6+6p) Step 3: Factor by groupingWe need to factor this expression. To do this, we will look for two numbers that multiply to 6+6p ...
You factorise the quadratic expression x²+ (a+b) x +ab by rewriting it as the product of two binomials (x+a) X (x+b). By letting (a+b)=c and (ab)=d, you can recognize the familiar form of the quadratic equation x²+ cx+d. Factoring is the process of reverse multiplicat...
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(b)Note: Attempt to factorise their trinomialquadratic.When multiplying out their two bracketed terms,it must produce at least two of their 3 trinomialterms(x- 11)(x+3) (2x- 1)Note: Must show all three terms collectedtogether for the final A markNote: Completely correct answer, but no...
Understand the meaning of the roots of an equation and how to find the roots of a quadratic equation. Also, see the formula used in finding the roots of a quadratic equation. Related to this Question Factorise: x^2 + y z + x y + x z. ...
For this, we express the complete polynomial as a product of two factors - the given factor and a second degree polynomial, and then we easily factorize this last polynomial by using the formula for a quadratic equation. Answer and Explanation: ...
Factorise an expression by taking out the common number factors 6a 6a + 12 = 6(a + 2) 5b – 15 = 5(b – 3) 4a + 2b = 2(2a + b) 3x – 2y = 3x – 2y no common factors here 4c – 10t = 2(2c – 5t) 12f + 15 = 3(4f + 5) 9y – 21n = 3(3y – 7n) ...
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