百度试题 结果1 题目(b) Factorise fully 6x^3-27x^2+30x=3x(2x2-9x+10) [M1]=3x(2x-5)(x-2) 相关知识点: 试题来源: 解析 =3x(2x²-9x+10) [M1] = 3x(2x-5)(x-2) 反馈 收藏
Analyze the roots of the following equations: (i)2x3−9x2+12x−(9/2)=0 (ii)2x3−9x2+12x−3=0 View Solution Free Ncert Solutions English Medium NCERT Solutions NCERT Solutions for Class 12 English Medium NCERT Solutions for Class 11 English Medium ...
Factor the given polynomial: 9x^3 - 24x^2 + 16x Factor the given polynomial: xy + 2x + y + 2 Factor the given polynomial completely: 10t^2 + 29t - 21 Factor the given polynomial: 10x^2 + 29x - 21 Factor the given polynomial: x^2 + 2x - 48 ...
If x+1 is a factor of ax^(3)+x^(2)-2x+4a-9, then value of a . 01:58 Factorise (i) x^(2)+9x+18 (ii) 6x^(2)+7x-3 (iii) 2x^(2)-7x-15 (... 05:20 Factorise (i) 2x^(3)-3x^(2)-17x+30 (ii) x^(3) -6x^(2)+11x-6 (iii... 20:06 Using suitable identi...
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View Solution Factorize each of the following expressions:9x2−4y2(ii)36x2−12x+1−25y2 View Solution Free Ncert Solutions English Medium NCERT Solutions NCERT Solutions for Class 12 English Medium NCERT Solutions for Class 11 English Medium ...
(i) x ^ 3 −2x ^ 2 −x+2 =x ^ 2 (x−2)−1(x−2) =(x−2)(x ^ 2 −1) =(x−2)(x+1)(x−1) (ii) x ^ 3 −3x ^ 2 −9x−5 =x ^ 3 −5x ^ 2 +2x ^ 2 −10x+x−5 =x ^ 2 (x−5)+2x(x−5)+1(x−5) =(x