Factorise : (a) x^(6)+y^(6) " " (b) x^(6)-y^(6) 04:30 Factorise a^(6)-b^(6). 01:32 Factorise : m^(6)-64n^(6) 03:08 Factorise : x^(6)-64 01:53 Factorise : a^(6)b^(6)-a^(3)b^(3)-6 01:33 Factorise the following. 2x - 6 01:27Exams...
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2 Factorise completely$$ 9 a ^ { 2 } + 6 a b + b ^ { 2 } - 2 5 c ^ { 2 } $$.$$ 9 a ^ { 2 } + 6 a b + b ^ { 2 } - 2 5 c ^ { 2 } \\ = ( 3 a + b ) ^ { 2 } - ( 5 c ) ^ { 2 } \\ = ( 3 a + b + 5 c ) ( 3 a + ...
相关知识点: 试题来源: 解析 (a)4x-10x-6.=2(2'-5x-3)[M시=2(2x+I)(x-3)(4)(b)10x'y-$xy+2x-1.=Sx(2x-1)+1(2x-1)IM1)=(5xy+I)(2x-I)( 反馈 收藏
Factorize completely. 4a^4 b^2 - 8a^3b^2 + 12a^3b Factorize: x^2 + 5 x + 6. Factorize: a) \ 3y^2+7y-20\b) \ x^2-6xy-27y^2 Factorize: 5a^2 b^2 - 10ab^2 + 25b^2. Factorize 4 x^3 - 5 x^2 + 7 x - 6. ...
NCERT solutions for CBSE and other state boards is a key requirement for students. Doubtnut helps with homework, doubts and solutions to all the questions. It has helped students get under AIR 100 in NEET & IIT JEE. Get PDF and video solutions of IIT-JEE Mains & Advanced previous year pap...
Factorise a ^(3) - 3a^(2) b + 3ab ^(2) -b ^(3) 01:38 Find the proudct (a-b-c) (a ^(2) + b ^(2) + c ^(2) - ab + bc-ca) witho... 02:33 Fractorise 27a ^(3) + b ^(3) + 8c^(3) -18-18 abc using identity. 02:51Exams...
11 Factorise the following completely.(a)$$ 1 6 a + 2 4 b $$(b)$$ - 3 x - 9 x ^ { 2 } $$(c)$$ x ( 2 z - 5 ) + y ( 5 - 2 z ) $$Answer (a) ···(1)(b)···[1](c)---|2) 相关知识点: 试题来源: 解析 11(a)8(2a + 3b)11(b...
百度试题 结果1 题目Factorise: a(x-a)(x+y)2-b(x-a)2(x+y). 相关知识点: 试题来源: 解析 (x-a)(r+y)(ar+ay- br+ab) 反馈 收藏
( x - y + a ) ( x - $$ (2) $$ y - a ) $$ (3)$$ ( x - 3 ) ( 7 x + y ) $$ $$ ( 2 a - b + $$ (4) $$ 4 ) ( 2 a - b - 4 ) $$ (5)$$ ) ( x - 2 y - 3 ) ( x - 2 y + 1 ) $$ (6)$$ ( a - b ) ( 1 - a ) ( b - 1 ...