百度试题 结果1 题目16 Factorise 6x^2+7x-20 .(3x-4)(2x+5) final answer..[2] 相关知识点: 试题来源: 解析 (3x-4)(2x+5) final answerB1 for (ax+b)(cx+d) where ac=6andad+bc=7 or bd=-20 反馈 收藏
(i) x^(2)+9x+18=x^(2)+6x+3x+18 {by splitting middle term] =x(x+6)+3(x+6)=)x+3(x+6) (ii) 6x^(2)+7x-3=6x^(2)+9x-2x-3 [by splitting middle term] (iii) 2x^(2) -7x -15=2x^(2) -10x+3x-15 [by splitting middle term] =2x(x-5)+3(x-5)=(2x+3)(x-5)
Factorise : - 12x^(2)-7x+1 01:17 Factorise : - 2x^(2)+7x+3 01:09 Factorise : - 6x^(2)+5x-6 01:38 Factorise : - 3x^(2)-x-4 01:14 Factorise : - x^(3)-2x^(2)-x+2 02:48 Factorise : - P(x)=x^(3)-3x^(2)-9x-5 02:41 Factorise : - x^(3)+13x^(2)+32...
Factorise :x4−7x2+1 View Solution Doubtnut is No.1 Study App and Learning App with Instant Video Solutions for NCERT Class 6, Class 7, Class 8, Class 9, Class 10, Class 11 and Class 12, IIT JEE prep, NEET preparation and CBSE, UP Board, Bihar Board, Rajasthan Board, MP Board,...