Factorise : x^(3) - 4x^(2) - 7x + 10 06:21 Factorise : 2x^(3) + 7x^(2) + 2x -3 07:21 Factorise : 3x^(3) + 14x^(2) - 7x - 10 06:58 Factorise : 6x^(3) + 13x^(2) + 9x + 2 06:43 Expand : (2x+3)(2x-5) 01:14 Expand :
Factorise the given expression completely: 6x^(2) + 7x -5 01:25 Factorise : x^(2) + (1)/(4x^(2)) + 1 - 7x - (7)/(2x) 01:48 Factorise : 9a^(2) + (1)/(9a^(2)) - 2-12a + (4)/(3a) 02:17 Factorise: x^(2) + (a^(2)+1)/ax +1 01:06 Factorise: x^(4)...
题目4. Factorise fully the following polynomials. You may need to use the factor theorem:(a) x^3+2x^2+x .(b) x^3-6x^2+11x-6 .(c) x^3-4x^2+5x-2 .(d) 2x^3+7x^2+2x-3 .(e) x^4-2x^2+1 . 相关知识点: 试题来源: ...
Factorize: 2x^2 - 15x - 8 = 0 Factorize: A) 2x^3 + 5x^2 6x + 9 \\B) 2x^3 + 9x^2 + 3x - 4 0 Factorize (x-y)^2 - (x-z)^2. Factorize: 7 (3 k - 1)^2 + 26 (3 k - 1) - 8 Factorize x^2 + 9 y^2 - 6 x y + 4 x - 12 y + 4. ...
(x^2-2^2) 4 and 16=4 4c2(2) Pifference between 2 squares (b) 72-12P^2=3125-4P^2 =3[5-(29)2] =3(5+2P)(5-2P) (C)2x2+10x+12 +3 x 3x =2(x^2+5x+6) 24 =2(x+3x+2) x2+6 50 (d)3x(2x-11)+15 -X =6x2-33x+15 X一 -10x =3(2x2-11x+5) 2x2 +5 -...
Factorise:25x2−9. Question: Factorise:25x2−9. Algebraic Identities: The quadratic expression that is given to factorize is set up in the form of the difference of two perfect squares. So, here we will apply the algebraic identities to factorize the given expression. The basic algebraic...
Factorize the polynomial. 3a^{2}-10a+8 Factorize the polynomial. x^{2} - 2x + 4 Factor the polynomial f(x). Then solve the equation f(x) = 0. Which is a factor of the polynomial f(x) = 6x^4 - 21x^3 - 4x^2 + 24x - 35? A) 2x - 7 B) 2x + 7 C) 3x ...
百度试题 结果1 题目Factorise fully the following:a)2x+8b)3x-12c) 6x +4d)18x-9 相关知识点: 试题来源: 解析 e0 2x+8=2(x+4) b) 3x-12= 3(x-4) 6x+4= 2(3x+2) 27 18x-9= 9(2x-1) 反馈 收藏
6x2+9x+2x+3 Step 5: Group the termsNext, we group the terms:(6x2+9x)+(2x+3) Step 6: Factor out the common factorsNow, we factor out the common factors from each group:- From the first group 6x2+9x, we can factor out 3x:3x(2x+3)- From the second group 2x+3, we can ...
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