It would depend on the field type, for instance, if if it is a date/datetime you can use the function: MONTH(date) Explained better here: https://learnsql.com/cookbook/how-to-get-the-month-from-a-date-in-mysql/#:~:text=Use%20the%20MONTH()%20function%20to%20retrieve%20a%20mo...
SQL>SELECT hiredate,2to_number(to_char(hiredate,'hh24'))时,3to_number(to_char(hiredate,'mi'))分,4to_number(to_char(hiredate,'ss'))秒,5to_number(to_char(hiredate,'dd'))日,6to_number(to_char(hiredate,'mm'))月,7to_number(to_char(hiredate,'yyyy'))年,8to_number(to_char(...
SELECTEXTRACT(YEARFROMdate_column)ASyear,COUNT(*)AScountFROMtable_nameGROUPBYyear; SQL Copy 上述示例中,我们使用SQL Extract函数从date_column列中提取年份,并统计每个年份对应的数据量。 4.2 计算日期或时间差值 SELECTTIMESTAMPDIFF(DAY,start_date,end_date)ASdays_diffFROMtable_name; SQL Copy 上述示例中,...
oracle中extract()函数从oracle 9i中引入,用于从一个date或者interval类型中截取到特定的部分 语法如下: extract ( {year|month|day|hour|minute|second }|{ timezone_hour|timezone_minute }|{ timezone_region|timezone_abbr }from{ date_value|interval_value } ) 只可以从一个date类型中截取年月日 SQL>se...
EXTRACT(YEAR_MONTH FROM date_registered) AS year_month_registered, COUNT(*) AS num_registered FROM `members` GROUP BY year_month_registered If you run the SQL query above, you will see that it returns the following result: As you can see, the Year and Month has been stored in a YYYY...
datetimeDATE、TIMESTAMP、TIMESTAMP WITH TIME ZONE、TIMESTAMP WITH LOCAL TIME ZONE、INTERVAL YEAR TO MONTH、INTERVAL DAY TO SECOND等数据类型的值。 说明 如果指定提取YEAR或MONTH,则datetime数据类型为DATE、TIMESTAMP、TIMESTAMP WITH TIME ZONE、TIMESTAMP WITH LOCAL TIME ZONE或INTERVAL YEAR TO MONTH。
显示当月之前所有结果的SQL查询 、 我在Oracle中有一个包含列的表: DATEID date,COUNT_OF_PHOTOS int这个表基本上表示每天上传的照片数量。我有一个汇总每月上传的照片数量的查询:fromp 浏览1提问于2012-07-19得票数0 2回答 子查询是否基于其他条件的“短路”?
extract(month from 后边应该直接跟日期格式就可以，你的t.TASK_STARTDATE字段类型不是date？？？改成：extract(month fromt.TASK_STARTDATE)= '12'
SQL> select extract(year from sysdate) as "year" from dual 2 / year --- 2012 2. 获取当前日期中的月份 SQL> select extract(month from sysdate) as "month" from dual 2 / month --- 8 3. 获取当前日期中的日 SQL> select extract(day from date'2012-12-28') as "day" from dual 2 ...
EXTRACT(unitFROMdate) 说明 以整数类型返回date的指定部分值。如果指定多个部分,则将所有值按顺序拼接。 有关参数unit的详细信息,请参见DATE_ADD。当unit为WEEK时,以周日为每周第一天。 示例 obclient>SELECTEXTRACT(WEEKFROM'2013-01-01'),EXTRACT(WEEKFROM'2013-01-06'),EXTRACT(YEAR_MONTHFROM'2012-03-09'...