“expression must have pointer-to-object type” 错误详解 1. 错误信息含义 错误信息“expression must have pointer-to-object type”通常表明在代码中使用了非指针类型的表达式,但在该上下文中编译器期望一个指向对象的指针类型。这通常发生在使用了指针操作(如解引用*、下标[]等)或尝试将非指针类型的变量传递给...
因为子文件中引用主程序定义的结构体出错。解决:将子程序文件中 子函数移至主文件。结构体也是一种数据类型，只不过在这种数据类型中又包含了几个基本的数据类型。构体变量在内存中的存放和基本数据类型变量在内存中的存放是不同的，基本数据类型的存放系统是会给分配一块连续的空间用来存放，而结构体...
pd is a pointer to the start of the array. pd[i] is an element of the array. In this case, you would use the "." operator instead of the "->" operator. Why do you think there are 8 elements in the array? pd[i] has type pointer to PictureBoxArray. Why do you think it ...
int m,n,i,a,b,c,a[900],j 两个变量a重复了。换个名字。
c语言为什么报错expression must have pointer-to-object type(代码很短) 代码还没有写完,写到贴上来的最后两行哪里j划了小红线,为什么报错呢?谢谢#include<stdio.h>intmain(){intm,n,i,a,b,c,a[900],j;while(scanf("%d%d",&m,&n)!=EOF){j=0;for(i=m;i<=n... 代码还没有
expression must have pointer-to-object type A = X[rows][1]; for ( count=0;count<Q;count++) { value_buf[count] = A[count]; // delay(); } #143 expression must have pointer-to-object type
请问下这个错误怎么解..RT,要求测试一个数列中的一个数必须等于前两个的和,例:0, 1, 1, 2, 3, 5, 8, 13, 21, 34, 55, 89, 144, 233, …然后17行就报出这种错误,怎么解决
expression must be a pointer to a complete object type问题补充:匿名 2013-05-23 12:21:38 null 匿名 2013-05-23 12:23:18 正在翻译,请等待... 匿名 2013-05-23 12:24:58 表示必须是尖对一个完全目标类型 匿名 2013-05-23 12:26:38 正在翻译,请等待... 匿名 2013-05-23 12:...
If bothexpressionandconditional-expressionhave the same structure, union, or pointer type, the type of the result is the same structure, union, or pointer type. If both operands have typevoid, the result has typevoid. If either operand is a pointer to an object of any type, and the other...
[translate] aBattery light 电池光[translate] aThe treasure 珍宝[translate] aexpression preceding parentheses of apparent call must have (pointer-to-) function type 明显的电话表示在先的括号必须有 (尖对) 作用类型[translate]