By Taking the LCM of 156, we will get the product of its prime factor.Hence, 156 = 2 × 2 × 13 × 3 × 1 = 22× 13 × 3(3)3825By Taking the LCM of 3825, we will get the product of its prime factor.Hence, 3825 = 3 × 3 × 5 × 5 × 17 × 1 = 32× 52× ...
1 index notation 什么意思哦句子是express the number 1960 as a product of prime factors,giving your answer as a product of prime factors in index notation. 2index notation 什么意思哦句子是express the number 1960 as a product of prime factors,giving your answer as a product of prime factors...
Express each number as a product of its prime factors : 7429 00:58 Find the LCM and HCF of the following pairs of integers and verify tha... 02:46 Find the LCM and HCF of the following pairs of integers and verify tha... 04:07 Find the LCM and HCF of the following pairs of int...
aCriteria that must be fulfilled for auditors to accept corrective action 必须履行为了审计员能接受惩治行为的标准[translate] aExpress a composite number as a product of prime of prime factors 表达一个合成数作为主因最初产品[translate]
Express 429 as a product of its prime factors. 01:16 A pole has to be erected at a point on the boundary of a circular p... 05:05 If m time the m^(th) term of an Arithmetic Progression is equal to n t... 03:43 The sum of the first three numbers in an Arithmetic Progressio...
19. (a) Express each of the following numbers as a product of their prime factors, giving your answer in index form.(i) 216000(ii) 518400(b) Hence find(i) $$ \sqrt [ 3 ] { 2 1 6 0 0 0 } $$,(ii) $$ \sqrt { 5 1 8 4 0 0 } $$,(iii) the HCF of 216 000 and ...
16. (a) Express the numbers 66 and 2520 as products of their prime factors.(h) Find the smallest positive integer. k. such that 2520k is a perfect cube.(c) Find the smallest positive integer. n. such that 66n is a multiple of 2520.Answer (a) 66 =|1]2520(b)k=121(c) n =...
To find the number of ways to express 1200 as a product of two co-prime factors, we will follow these steps:Step 1: Prime Factorization of 1200 We start by finding the prime factorization of 1200.1. Divide 1200 by 2:
剑桥几道初中试题求解(英文版)1 Express 99 as the product of its prime factors.2 The length of a piece of string is 0.026 metres, correct to the nearest millimetre.Write down, in millimetres, the lower bound of this length.Answer3 A
To express the numbers 432 and 10125 as a product of powers of their prime factors, we will follow these steps:Step 1: Prime Factorization of 4321. Divide by 2 (the smallest prime number): - 432 ÷ 2