operatorint()const; operatordouble()const; }; voidf2(longdouble); intmain() { Aa; f2(a);//二义性错误,含义是f(A::operator int())还是f(A::operator double()) longlg; Aa2(lg);//二义性错误:含义是A::A(int)还是A::A(double) return0; } 1. 2. 3. 4. 5. 6. 7. 8. 9. ...
operatordouble()const//转换Rational类成 double类型 { } operatorstring()const//转换Rational类成 string类型 { } }; str = ra;//执行operator string ()转换string 运行崩溃 i =1*ra;//执行operator double()转换成double型 cout<<ra;//执行operator double() 转换成double型输出随机浮点数 所以避开类型...
出错原因:在遇到操作符+时,a.可以调用Fraction的操作符重载函数Fractionoperator+(const Fraction&f),则需要将4通过隐式构造转换成Fraction类型,再做+操作;b.也可以将+看作全局操作符,此时又可以将f转换成double,进行+操作。因为a,b两种都可行,所以编译器无法自动选择哪种方式运行,故报错。此时将Fraction类中的doub...
classFraction{public:Fraction(intnumerator,intdenominator=1):m_numerator(numerator),m_denominator(denominator){}//转换函数operatordouble()const{return(double)m_numerator/m_denominator;}private:intm_numerator;//分子intm_denominator;//分母};intmain(){Fractionf(3,5);doublesum=4+f;std::cout<<"sum...
#include<iostream>usingnamespacestd;classFraction{public:Fraction(intnumerator,intdenominator =1): m_numerator(numerator), m_denominator(denominator){}explicitoperatordoubleconst{return(double)m_numerator/m_denominator;}private:intm_numerator;intm_denominator;} ...
operator double() const { return (double)1.0; } }; Cube c(3,5);//这里重载的是c + c; c.operator+(c); //应该是c.operator+(int) Cube c2 = c + 4;//错误,二义性 //隐式转换,4可行;就会是c(3,5) + c(4,1);可行 //c转化为double可行,double + 4,再转化为Cube 可行; ...
operatordouble()const//转换Rational类成 double类型 { } operatorstring()const//转换Rational类成 string类型 { } }; str = ra;//执行operator string ()转换string 运行崩溃 i =1*ra;//执行operator double()转换成double型 cout<<ra;//执行operator double() 转换成double型输出随机浮点数 ...
Fraction类的代码如下。转换函数的定义为：在转换函数中，使用了关键字operator，表明这是一个运算符函数。函数名为double，表示将Fraction转换为double类型。const限制符确保函数内不会改变数据成员的值。分子除以分母以实现转换，注意使用了double强制转换以避免整数运算。测试代码示例：当编译器遇到此代码时，...
Franctionoperator+(constFranction&f){returnFranction(this->m_numerator+f.m_numerator,this->m_denominator+f.m_denominator);} //类型转换函数 // operator double(){ return static_cast(m_denominator/m_denominator);} private: intm_numerator; ...
#include<bits/stdc++.h>using namespace std;class Fraction{private:intm_numerator;// 分子intm_denominator;// 分母public:Fraction(intnum,intden=1):m_numerator(num),m_denominator(den){}operatordouble()const{returndouble(m_numerator)/m_denominator;}};intmain(){Fractionf(3,5);doubled=4+f;co...