expected value of a probability distribution 一种概率分布的期望值 average value of a probability distribution 概率分布的均值 mean of a probability distribution 概率分布的均值 variance of a probability distribution 一个概率分布的方差 probability distribution of a continuous variable 连续变量的概率分布...
网络一种概率分布的期望值 网络释义 1. 一种概率分布的期望值 www.dictall.com|基于5个网页
The expected value of the a probability distribution A. Is the same as the random variable. B. Is another term for the mean. C. Is also called the variance. D. Cannot be greater than 1. 相关知识点: 试题来源: 解析 B 反馈 收藏 ...
Expected Value =Σ(Probability of Event * Value of Event) 其中,Σ表示求和,Probability of Event是事件发生的概率,Value of Event是该事件发生的值或结果。 以一个简单的例子来说明: 假设你有三种投资选择,A、B和C,它们的预期回报和对应的概率分别是: A: 5%的概率获得100元 B: 30%的概率获得200元 C:...
expected value of a lottery game shows how unfairly it is constructed. Suppose for $1 you choose six numbers from 1 to 48. The probability of choosing all six numbers correctly is 1/12,271,512. If you win $1 million for getting all six correct, what is the expected value of this ...
Expected value:n. the sum of the values of a random variable with each value multiplied by its probability of occurance. 直译为:对随机变量的每个值乘以其出现的概率, 然后求和。 比如对于一个离散分布的随机变量: 可以发现,期望也是一种平均值或者叫加权平均值,但往往难以获取随机变量所有可能的值及其概率...
Expected value:n. the sum of the values of a random variable with each value multiplied by its probability of occurance. 直译为:对随机变量的每个值乘以其出现的概率, 然后求和。 比如对于一个离散分布的随机变量: 可以发现,期望也是一种平均值或者叫加权平均值,但往往难以获取随机变量所有可能的值及其概率...
In many applications in decision theory and expert systems we may have information regarding the probability of some variable being equal to a fuzzy subset. In this paper we provide a methodology for using this information to obtain the expected value of the variable....
4. conditional probability and independent event条件概率就是发生概率的时候有特定条件,比如生病的概率中感冒的概率独立事件是说2个事件发生没有内部关联比如生病和看病花的钱5. population parameter and sample statisticspopulation 是说正个的真实值,是我们想要的,但是我们不知道,所以就要估计(Estimate parameter) 就...
(2)(a) First find out the profit =(1/6)(4)+(5/6)(0) =2/3And then the expected value of the prize =-1+2/3 =-1/3(b) The favoured outes are 3 and 6.So profit =(2/6)(3)+(4/6)(0) =1And then the expected value of the prize =-1+1 =0 ...