这将导致 "expected 'package', found 'func'" 错误,因为文件中缺少 package 声明。正确的文件应该如下所示: go package main import "fmt" func main() { fmt.Println("Hello, World!") } 在这个修正后的文件中: package main 声明了该文件属于 main 包。 import "fmt" 导入了 fmt 包,使得我们可以使...
package main import"fmt" func addnumbers(a, b int) int { returna + b } func main() { result := addnumbers(5)// 错误:预期分号,但发现了左括号 } 在此示例中,addnumbers 函数需要两个参数,但在调用时只传递了一个。您应该使用以下正确的调用语法: 1 result := addNumbers(5, 10) 理论要掌...
I have go on both my system and I am having the same issue after installing go and trying to run a go file "go:1:1: expected 'package', found 'EOF'" package main import "fmt" "os" func main() { var s, sep string for i := 1; i < len(os.Args); i++ { ...
import "fmt" //导入fmt格式化包 func main(){fmt.Println("hello golang")} //main主函数入口 1. 2. 3. 4. 5. 运行 go run hello.go 1. 结果 hello golang 1. 但是如上的代码,并不美观,go提供了格式化代码命令 go fmt hello.go 1. 格式化后,代码风格如下 package main import "fmt" func mai...
import "fmt" func main() { var x string = "Hello World" fmt.Println(x) } ~~~ but when I do go run main,go I see this error : main.go:1:1: expected 'package', found 'EOF' which surprise me because line 1 starts with a package ...
expected declaration, found 'IDENT' 今天偶然遇到这个错误,错误使用场景如下: packagemainimport"fmt"M:=map[int]string{1:"a",2:"b",}funcmain(){fmt.Println(M)} 这个是因为:=操作符导致的,:=不能用于声明全局变量!只能在函数内部使用。 :=只用来声明临时变量, 初始化全局变量需使用var关键字,正确操作...
为什么在代码的最外层调用fmt: package main import "fmt" fmt.Println("fmt") 提示expected declaration, found 'IDENT' fmt 还有同样在最外层,这样赋值会有问题: package main var n int64 // expected declaration, found 'IDENT' n n = 99 //var n int64 = 88 //这样写为什么就没有问题? 原因是什么...
facing "expected declaration, found 'package' " error while trying to run https://play.golang.org/p/ZdFpbahgC1 : // Go's `math/rand` package provides // [pseudorandom number](http://en.wikipedia.org/wiki/Pseudorandom_number_generator) //...
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为什么在代码的最外层调用fmt: package main import "fmt" fmt.Println("fmt") 提示expected declaration, found 'IDENT' fmt 还有同样在最外层,这样赋值会有问题: package main var n int64 // expected declaration, found 'IDENT' n n = 99 //var n int64 = 88 //这样写为什么就没有问题? 原因是什么...