意思是:在"{"的前面少了一个“;copy”,把“;”补上,错误即可消失。错误示例:1、error: expected expression before ‘/’ token和In function ‘main’.意思是:C++的语法错误。2、expected initializer before '<' token.意思是:借鉴里面问没有指定名字空间的问题,重新把boost库的路径放到了...
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So I'm having a problem with my code. I'm trying to make a program for linear regressions and everything else is working for now but I'm stuck on the error that says 'expected primary-expression before 'float''. Please help.
but they still exist. I used one near the bottom of my code. I keeping getting the error: expected primary-expression before 'float' and im not sure what I am doing wrong. I probably didn't code this in the best manner but oh well. what can I say im a noob.:) help would be ...
首先,printf不是这样用的,其次,你把float类型和int类型拿去做算术运算,当然会出错。
printf("Total:%f\n", (float)deposit * pow((1 + 2.25%), 1)); break; case '2': printf("Total:%f\n", (float)deposit * pow((1 + 2.43%), 2)); break; case '3': printf("Total:%f\n", (float)deposit * pow((1 + 2.70%), 3)); break; case '5': printf("Total:%f\n"...
逗号前面有语法错误,具体是哪个逗号,应该还有行号提示的,你错误信息没有复制完整。
swap(int x,int y); 去掉 2 个 int swap(float a,float b)); 去掉 2 个 float 函数调用要好好去复习一下,你这不是调用,也不是声明!!!
if(c==+){printf("%f",a+b);改为 if(c=='+') printf("%f",a+b);即:+用单引号,将大括号{删掉。
解析 #include "stdafx.h"#include #include using namespace std;int main(){ float a,b,c,x1,x2,d; couta>>b>>c; d=b*b-4*a*c; if(d>=0) { x1=(-b+sqrt(d))/(2*a); x2=(-b+sqrt(d))/(2*a); cout 反馈 收藏