LeetCode 171 Excel Sheet Column Number 解题报告 题目要求 Given a column title as appear in an Excel sheet, return its corresponding column number. For example: A -> 1 B -> 2 C -> 3 ... Z -> 26 AA -> 27 AB -> 28 ... 题目分析及思路 给出excel表格中的列标题,要求返回对应的列...
Given a column title as appear in an Excel sheet, return its corresponding column number. For example: A -> 1 B -> 2 C -> 3 ... Z -> 26 AA -> 27 AB -> 28 Credits:Special thanks to@tsfor adding this problem and creating all test cases. Solution: classSolution {public:inttitl...
Related to questionExcel Sheet Column Title Given a column title as appear in an Excel sheet, return its corresponding column number. For example: A -> 1 B -> 2 C -> 3 ... Z -> 26 AA -> 27 AB -> 28 1. 2. 3. 4. 5. 6. 7. class Solution(object): def titleToNumber(sel...
AC代码:(从右往左) publicclassSolution {publicinttitleToNumber(String s) {intres=0;for(inti=s.length()-1;i>=0;i--) res+=(s.charAt(i)-'A'+1)*((int)(Math.pow(26,s.length()-i-1)));returnres; } } 1. 2. 3. 4. 5. 6. 7. 精简版AC代码:(从左往右) publicclassSolution ...
链接:https://leetcode-cn.com/problems/excel-sheet-column-number 思路: 1、这道题是将26进制的数转换为10进制的数 Python代码: classSolution(object):deftitleToNumber(self,s):""" :type s: str :rtype: int """ret=0foritemins:temp=ord(item)-64ret=ret*26+tempreturnret ...
题目地址:https://leetcode.com/problems/excel-sheet-column-number/description/ 大意:就是一个简单的26进制表达式,A代表1,Z代表26.然后将26进制转化为10 进制。 那就是每一位乘以26的位数减一的次方。那就很简单了。 # 171. Excel Sheet Column NumberclassSolution:deftitleToNumber(self,s):""" ...
Related to questionExcel Sheet Column Title Given a column title as appear in an Excel sheet, return its corresponding column number. For example: A -> 1 B -> 2 C -> 3 ... Z -> 26 AA -> 27 AB -> 28 Credits: Special thanks to@tsfor adding this problem and creating all test ...
Given a column title as appearinan Excel sheet,returnits corresponding column number. For example:A->1B->2C->3... Z->26AA->27AB->28 分析 有了上一题的经验,这次要容易得多了。它的题意也能理解了,就是从上面的实例左侧字符转换成右侧的数字。大家可以看看上一题:LeetCode 168 Excel Sheet ...
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impl Solution { pub fn title_to_number(column_title: String) -> i32 { // 维护 ans ,表示最终列号 let mut ans = 0; // 遍历 column_title ,计算列号 for &ch in column_title.as_bytes() { // 列号是 26 进制,但每一位都是从 1 开始计数的, // 也就是取值范围是 [1, 26] , //...