Rewrite√−1(16)-1(16)as√−1⋅√16-1⋅16. √−1⋅√16-1⋅16 Rewrite√−1-1asii. i⋅√16i⋅16 Rewrite1616as4242. i⋅√42i⋅42 Pulltermsout from under the radical, assuming positive real numbers. i⋅4i⋅4 ...
Evaluate integral from 9 to 16 of square root of x-1 with respect to x( (∫ )_9^(16)√x
Evaluate square root of 1/((1/4)^2)(√(1/(((1/4))^2))) 相关知识点: 试题来源: 解析 Apply the product rule to ( 1/4).(√(1/((1^2)/(4^2)))Multiply the numerator by the reciprocal of the denominator.(√(1(4^2)/(1^2)))Multiply( (4^2)/(1^2)) by ( ...
Evaluate 5^3- square root of 16*(2^4+(6^2-6^0)÷7) − √ ⋅ (24+(62−60)÷7) Simplify eachterm. Tap for more steps... Raise5to theof3. 125-16⋅(24+(62-60)÷7) Rewrite16as42. 125-42⋅(24+(62-60)÷7)...
Error: 6199 Attempt to evaluate real square root of negative number.Login
Evaluate square root of 19 √1919 The result can be shown inmultipleforms. Exact Form: √1919 Decimal Form: 4.35889894…4.35889894… 2√19192 ( ) | [ ] √ ≥ 7 8 9 ≤ ...
Evaluate integral of square root of 1+y^2 with respect to y 答案 Let , where . Then . Note that since , is positive.Simplify .Multiply by by adding the exponents.Factor out of .Integrate by parts using the formula, where and .Raise to the power of .Raise to the power of .Use the...
Evaluate integral from 0 to 4 of x/( square root of 1+2x) with respect to x 答案 Let . Then , so . Rewrite using and .Simplify.Since is constant with respect to , move out of the integral.Apply basic rules of exponents.Expand .Rewrite as .Split the single integral into multipleinte...
Evaluate - square root of 49 −√49-49 Rewrite4949as7272. −√72-72 Pulltermsout from under the radical, assuming positive real numbers. −1⋅7-1⋅7 Multiply−1-1by77. −7-7 −2√49-492 ( ) | [ ] √ ≥
Note: Since this application uses the functions defined in math, you need to consider that some of these functions will raise a ValueError when you call them with an invalid input value. For example, math.sqrt(-10) would raise an error because the square root of -10 is undefined. Later...