x=stack[top--]; y=stack[top];if(expr[i]=='+') stack[top]=y+x;elsestack[top]=y-x; }elsereturnInfinity; } }elseif(expr[i]=='*'||expr[i]=='/') {if(top) { x=stack[top--]; y=stack[top];if(expr[i]=='*') stack[top]=y*x;else{if(x) stack[top]=y/x;elseretur...
Write a program to evaluate a postfix expression. You only have to handle four kinds of operators: +, -, x, and /. ElementTypeEvalPostfix(char*expr ); whereexprpoints to a string that stores the postfix expression. It is guaranteed that there is exactly one space between any two operators...
Push 32-bit result onto stack.The bi in bipush stands for the byte integer type; the i in istore_1, iload_1, and isub stands for the 32-bit integer type. The compiler has converted the expression into an int value. It makes sense to do so because of the close relationship between ...
Loop through all Postfix tokens If token is a numeric, then add to a stack If token is an operator, then pop two numerics from the stack and evaluate Push the evaluated value back into the stack If more than one value exists in the stack, our RPN expression is incorrect and return so...
Push 32-bit result onto stack.The bi in bipush stands for the byte integer type; the i in istore_1, iload_1, and isub stands for the 32-bit integer type. The compiler has converted the expression into an int value. It makes sense to do so because of the close relationship between ...