微积分definite integralEvaluate the definite integral.form 0 to a/19x^37 (a^2-x^38)^1/2 dx (a > 0) 答案 = From 0 to a/19 (a^2-x^38)^1/2 d x^38/38replace x^38 with y,derives=From 0 to (a/19)^38 (a^2-y)^1/2 d y/38again replace (a^2-y)^1/2 with z= ...
百度试题 结果1 结果2 题目Evaluate the definite integral. 相关知识点: 试题来源: 解析 $\は準基う 结果一 题目 Evaluate the definite integral. 答案 4 相关推荐 1Evaluate the definite integral.反馈 收藏
Evaluate the definite integrals: a.∫01ex⋅sin(2+ex)dx ∫01e5xdx Definite Integral in Calculus: We are given two definite integral problems. To solve the given problem, we'll apply u-substitution, which is a process of change of variable to ge...
Evaluate the definite integral: \ \int (2x - 1)dx Evaluate the definite integral \int_{ - 1}^3 {(3{x^2} - x)dx} . Evaluate the definite integral \int _0^2 3x^ 5+2x \ dx Evaluate the definite integral \int _2^5 \frac{2}{1+x} \ dx Evaluate the d...
Evaluate the definite integral.form 0 to a/19x^37 (a^2-x^38)^1/2 dx (a > 0) 扫码下载作业帮搜索答疑一搜即得 答案解析 查看更多优质解析 解答一 举报 = From 0 to a/19 (a^2-x^38)^1/2 d x^38/38replace x^38 with y,derives=From 0 to (a/19)^38 (a^2-y)^1/2 d y/38...
题目 Evaluate the definite integral∫_(-2)^12xdx 答案 =-3. 结果二 题目 【题目】Evalu ate thedefi niteinteg ralf2 xdx. 答案 【解析】 = _ -3. 结果三 题目 【题目】Evaluat ethe integral. \$\$ 答案 【解析】 \$\$ 相关推荐 1Evaluate the definite integral∫_(-2)^12xdx 2【...
Evaluate the definite integral.form 0 to a(1/19)x^37 (a^2-x^38)^1/2 dx (a > 0) 相关知识点: 试题来源: 解析 LZ,here is the answer.∫x^37 (a^2-x^38)^1/2 dx1/38∫(a^2-x^38)^1/2 dx^38-1/38∫(a^2-x^38)^1/2 d(a^2-x^38)-1/57∫d(a^2-x^38)^3/2form...
Answer to: Evaluate the definite integral by interpreting it in terms of area. a) \int^0_{-3} (1 + \sqrt {9 - x^2}) dx b) \int^{10}_0 |x - 5| dx...
The definite integral is an indefinite integral with some fixed bounds known as the limits of the definite integral. The result of the definite integral is a value as the final answer and does not contain any constant of integration. To evaluate the definite integral fundamental theorem of ...
To evaluate the definite integral ∫32dxx2−1, we can follow these steps: Step 1: Factor the DenominatorThe first step is to factor the denominator x2−1:x2−1=(x−1)(x+1)Thus, we can rewrite the integral as:∫32dx(x−1)(x+1) Step 2: Use Partial Fraction Decomposition...