vector<string> cars = {"Volvo", "BMW", "Ford", "Mazda"}; cars.erase(cars.begin() + 1); for (string car : cars) { cout << car << "\n"; }Try it Yourself » Definition and UsageThe erase() function removes an element or a range of elements from a vector. The elements ...
修改end操作）导致it的值锁定的值变了，删除效果变了template<typename_Tp,typename_Alloc>typenamevector<...
问调用vector.erase() cpp时出现异常EN一.异常信息 The 'cursor' option is required, except for agg...
查看MSDN,对于erase的返回值是这样描述的:An iterator that designates the first element remaining beyond any elements removed, or a pointer to the end of the vector if no such element exists,于是改代码: for(vector<int>::iterator iter=veci.begin(); iter!=veci.end(); iter++) { if( *iter ...
vector<int>::iterator it; for(i=0;i<5;++i) ivec.push_back(i); for(i=0;i<5;++i) ivec.push_back(i); //it = remove_if(ivec.begin(),ivec.end(),compare); it=remove(ivec.begin(),ivec.end(),3); ivec.erase(it,ivec.end()); ...
问无法在C++ vector<pair<>>中调用erase()操作EN1、定义vector<vector<int>> A;//错误的定义方式vector<vector<int> > A;//正缺的定义方式2、插入元素若想定义A = [[0,1,2],[3,4,5]]，则：//正确的插入方式vector<vector<int> > A;//A.push_back里必须是vectorvector<int> B;B.push_back(0...
The C++ deque::erase function is used to delete either a single element or a range of elements from the deque. It reduces the size of the deque by number ...
The erase function does not modify the capacity of the vector, only its size. Example 复制 // vector_erase.cpp // compile with: /EHsc #include <vector> #include <iostream> using namespace std; int main() { vector <int> vec; vector <int>::iterator pos; vec.push_back(10); vec....
Edit & run on cpp.sh here is the error code : no matching function for call to 'std::vector<std::basic_string <char>> :: erase (std::string&) Last edited on Apr 19, 2013 at 4:25am Apr 19, 2013 at 4:37am closed account (3qX21hU5) Its because you are passing game_list...
{}", v); std::println("Erased even numbers: {}", erased); std::inplace_vector<std::complex<double>> nums{{2, 2}, {4, 2}, {4, 8}, {4, 2}}; std::erase(nums, {4, 2}); // since U = T, the value type can be ommited std::println("After erase {4, 2}, nums =...