std::vector<int>v={1,2,3,2,4,5}; intkey=2; erase(v,key); for(inti:v){ std::cout<<i<<' ';// 1 3 4 5 } return0; } DownloadRun Code That’s all about erasing elements from a vector in C++. Also See: Erase an element from a vector by index in C++ ...
问调用vector.erase() cpp时出现异常EN一.异常信息 The 'cursor' option is required, except for agg...
vector<int>vec; vec.push_back(123); vec.push_back(456); vector<int>::iterator findit=find(vec.begin(),vec.end(),123); //vector<int>::iterator findit = find(vec.begin(),vec.end(),111); if(findit==vec.end()) { printf("no find\n"); } else { printf("find[%d]\n",*fi...
Remove an element from a vector:vector<string> cars = {"Volvo", "BMW", "Ford", "Mazda"}; cars.erase(cars.begin() + 1); for (string car : cars) { cout << car << "\n"; }Try it Yourself » Definition and UsageThe erase() function removes an element or a range of ...
问在模板中使用vector::erase时，将常量迭代器作为‘this’参数传递会丢弃限定符EN类型说明符，随后紧跟着一个或者多个变量名组成的列表，其中变量名以逗号分隔，最后以分号结束。容器
Learn how to erase elements from a specific position in a C++ vector. This guide provides examples and explanations for effective vector manipulation.
for(vector<int>::iterator iter=veci.begin(); iter!=veci.end(); iter++) { if( *iter == 3) veci.erase(iter); } 乍一看这段代码,很正常。其实这里面隐藏着一个很严重的错误:当veci.erase(iter)之后,iter就变成了一个野指针,对一个野指针进行 iter++ 是肯定会出错的。
用下面的方法纠正std::vector iterator的失效是否有效? No. From cppreference 使迭代器和引用在擦除点或之后失效,包括end()迭代器。 v.erase(v.begin());已使所有迭代器无效。使用it具有未定义的行为。 迭代器和&迭代器的区别是什么? Case 1 auto关键字(不使用&)推断出non-reference类型。这意味着在您的案...
Position just beyond the last element removed from the vector. Return Value An iterator that designates the first element remaining beyond any elements removed, or a pointer to the end of the vector if no such element exists. Example // vector_erase.cpp // compile with: /EHsc #include <vec...
erase_if( std::vector<T, Alloc>& c, Pred pred ); (2) (since C++20) 1) Erases all elements that compare equal to value from the container. Equivalent to auto it = std::remove(c.begin(), c.end(), value); auto r = c.end() - it; c.erase(it, c.end()); return r;2...