products C. equilibrium state D. reverse reaction 相关知识点: 试题来源: 解析 B。平衡常数大说明反应更倾向于生成产物。选项 A“reactants”表示反应物;选项 B“products”表示产物;选项 C“equilibrium state”表示平衡状态;选项 D“reverse reaction”表示逆反应。所以答案是 B。反馈 收藏 ...
SAT 2 the equilibrium constant of a reaction changes as the concentration of the reactants changes.为什么是错的,反应物浓度不影响平衡吗?题干是醋酸的电离平衡.STATEMENT II解释是Changes in the concentrations of reactants and products do not affect the value of the equilibrium constant; if the ...
+/c=0.521V,2c=0.337V 相关知识点: 试题来源: 解析 解电极反应Cu+(ac+)+e-Cu(s)=0.521VCu2+(ac2+)+2e-==Cu(s)2+cu=0.337VE=-=-2+=0.521-0.337=0.184(V)AG = -nFE= -2. 2×96485×0.1846.222.303×8.314×298K=1.66×10 反馈 收藏 ...
a等一下他要出去 And so on he must exit[translate] afind the equilibrium constant for this reaction 发现平衡常数为这反应[translate]
解析 解 电极反应 Cu(acu )+e=Cu(s) \varphi_(Cu)⋅ρ_(Cu)=0.521V Cu2+(acu2)+2e-=Cu(s) e \varphi_(Cu)^2⋅x_(i1)=0.337V E =2-2=-2/=0.521-0. 337 =0.184(V) △G=-nFE^-=-2.303RTlgK^0 lgK^θ=(2*9648*0.184)/(2.303*8.314*298)=6.22 K^θ=1.66*10^6 ...
36 at 325 K and 100 kPa.What is the percent conversion of N2 O4 ?N_2O_4(g)⇌2NO_2(g))(Colorless)(Brown) 相关知识点: 试题来源: 解析 2.10 K^θ=2.25 ,HI的转化率=65.4% 2.11 Q =1.16,反应逆向进行 2.12 K^θ=0.54,△_rG_m=11.9kJ⋅mol^(-1) ,反应逆向进行 反馈 收藏 ...
Should the company plan, develops the latent customer positively, success implementation visiting, the capture customer demand. [translate] aThe equilibrium constant for this reaction greatly favors the formation of SAH. 平衡常数为这反应很大地倾向SAH的形成。 [translate] ...
SAT 2 the equilibrium constant of a reaction changes as the concentration of the reactants changes.为什么是错的,反应物浓度不影响平衡吗?题干是醋酸的电离平衡.STATEMENT II解释是Changes in the concentrations of reactants and products do not affect the value of the equilibrium constant; if the ...
For a reversible reaction: aA + bB → cC + dD The equilibrium constant, K, is equal to: K = [C]c·[D]d/[A]a·[B]b where [A] = equilibrium concentration of A [B] = equilibrium concentration of B [C] = equilibrium concentration of C ...
the value of equilibrium constant for the reaction HI(g)⇔1/2H2(g)+1/2I2(g)is8.0 The equilibrium constant for the reaction H2(g)+I2(g)⇔2HI(g)will be View Solution The equilibrium constant of the reactionSO2(g)+1/2O2(g)⇔SO3(g)is4×103atm−1/2. The equilibrium constant...