To write4as awith a,by22. b=4⋅22-12 4and22. b=4⋅22-12 b=4⋅2-12 4by2. b=8-12 Subtract1from8. b=72 b=72 b=72 b=72 b=72b=72 Now that the values ofmm(slope) andbb(y-intercept) are known, substitute them intoy=mx+by=mx+bto find theequationof theline. ...
Find the Equation Using Two Points (2,4) , (6,5), Step 1 Use to calculate the equation of the line, where represents the slope and represents the y-intercept. To calculate the equation of the line, use the format.Step 2 Slope is equal to the change in over the change in , or...
Using the two points given, write the linear equation in slope-intercept form.(5, 10) and (2, 8)HTML B / A A X Q12pt 相关知识点: 试题来源: 解析 (9 12(5,10) X21y2(21) S70Pe(m)=(y_2-y_1)/(x_2-x_0) ! 2-5 3 sm Jo find yinkup bE y1-M.X13 bEy2-MX2 b=(20...
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To find the equation of a line when given two points on the line, we first find the slope and then find they-intercept. Theslopeis the ratio of the change in the y-value over the change in the x-value. Given any two points on a line, you can calculate the slope of the line by...
Do perpendicular lines have same y intercept? Perpendicular lines do not necessarily have the same y-intercept. The only time this will happen is when their point of intersection is on the y-axis. What slope is perpendicular to m =- 3? To find the slope that is perpendicular to m=-3,...
Find the slope of the line that passes through the points (−2,6)(−2,6) and (1,4)(1,4). Solution Example 8: Identifying the Slope and y-intercept of a Line Given an Equation Identify the slope and y-intercept, given the equation y=−34x−4y=−34x−4. Solution As ...
To find the slope of the line from this equation, take the m value. To find the x and y intercept points for this equation, we start out by making y =0 and solving the problem for x. y=mx+b 0=mx+b -b=mx -b/m= x is the x intercept. To find the y intercept we change ...
intercept with x- and y- axis at points A(-4, 0) and B(0, 4), respectively. Step 1. m = (4-0)/(0-(-4))= 1 Step 2. Pick point A. Key in its x and y coordinates to find constant C. y = mx + C y = x + C -4 = 0 + C C = -4 There...