So far we have seen that a straight line can be described as a line with a constant gradient and we know how to find the gradient of any particular line from a graph of the line. In this section we shall look more closely at the co-ordinates of points on a straight line to see ...
Example 2. Find the equation of a line passing through two points M(1, 3) and N(2, 3). Solution. It is impossible to use Equation of the line passing through two different points, since My - Ny = 0. Find the Parametric equations of this line. We use MN as direction vector of...
24 The equation of a straight line is 3y + 2x + 6 =0.Find(a) the gradient of the line,Answer[1](b) the coordinates of the point where the line intersects the y-axis,(0,-2)Answer (...,...) [1](c) the coordinates of the point at which the line intersects the line y=...
Let AB be a straight line parallel to x-axis at a distance b units from it.Then, clearly, all points on the line AB have the same ordinate b. Thus, AB .can be considered as the locus of a point at a distance b from x-axis and allpoints on the line AB satisfy the condition y...
There are 3 steps to find the Equation of the Straight Line :1. Find the slope of the line 2. Put the slope and one point into the "Point-Slope Formula" 3. SimplifyStep 1: Find the Slope (or Gradient) from 2 PointsWhat is the slope (or gradient) of this line?
Vector Equation of a Line We can use vectors to create the vector equation of a line. In order to create the vector equation of a line we use the position vector of a point on the line and the direction vector of the line. In order to find the direction vector we need to understand...
Here is an example of a generic equation: Some users wish to write thesubstitutedform of an equation, with the actual fitted values for the parameters. For all but the simplest equations, this may be a bit awkward: More on writing equations. ...
7. a) Find the equation of the line which is perpendicular to the line y=2x+ 1 and passes through (3,3).b) Find the exact coordinates of the point of intersection of the line you found in part a) and the line y=2x+1This distance is the perpendicular distance c) Hence find, ...
The equation of the straight line L is kx+4y-2k=0, where k is a constant. If L is perpendicular to the straight line 6x-9y+4=0, find the y-intercept of L( ).直线L的方程为kx+4y-2k=0,其中k为一常数.若L垂直于直线6x-9y+4=0,求L的y截距( ). A: -3 B: -2 C: 2 D:...
-tree.numTopModules()-聚类之后的总数,2365个聚类-tree.codelength()-每个聚类中平均有多少个词-addLink(self,n1,n2,weight=1.0)-_infomap.Infomap_addLink(self,n1,n2,weight),可以[点1,点2,权重] 4.1 v0.x版本 直接看苏神的代码即可,跟Word2Vec配合,跑一个词聚类的例子,代码位于:https://github.com...