Use implicit differentiation to find an equation of the tangent line to the curve at the given point.ysin(8x)=xcos(2y) ,((π/2,π/4)y= 相关知识点: 试题来源: 解析 stepl:Findthederwhey_(S1^3)8x=xws2y y(8w58x)+(51308x)y'=x(-2y5302y +cos2-y yyy'=(-8y-los8x+cos2y)/(...
百度试题 结果1 题目Use implicit differentiation to find an equation of thetangent line to the curve atthe given point.2(x^2+y^2)^2=25(x^2-y^2) (3,1)(lemniscate)y0 相关知识点: 试题来源: 解析 y=-9/(13)x+(40)/(13) 反馈 收藏 ...
100分求一道数学题,Find an equation for the tangent line to the curve x^2y + xy^3 = 2 at the point (1; 1). 答案 题目意思是,求曲线 x^2y + xy^3 = 2在点(1,1)处的切线方程.对方程两边取全导,d(x^2y)+d(xy^3)=2,2xydx+x^2dy+y^3dx+3xy^2dy=0,整理得 dy/dx=-(2xy+y^...
EXAMPLE 7 Find the equation of the tangent line to the graph of y = tan x at the point (w/4, 1). 相关知识点: 试题来源: 解析 SOLUTION The derivative of y=tanxsin(dy)/(dx)=sec^2x . When x = #/4, the derivative is equal t sec^(2π)=(2/(√2))^2=2 = 2. Thus the ...
Let the equation of the tangent line be y= -x +b. Substituting this into the equation of the circle: 2x^2- 2bx+b^2-4=0 . Since the line is tangent to the circle, we have △=(-2b)^2-4*2(b^2-4)=0 Solving for b: b =±2 2. So the equation of the tangent line is ...
题的意思是：求f(x)=8/√(x^2+3x)在点(1,4)处的切线方程 重点是求函数在x=1处的f'(x)直接求导很麻烦，可采用对数求导法，lnf(x)=ln8-(ln(x^2+3x))/2 两边同时对x求导，f'(x)/f(x)=-(2x+3)/2(x^2+3x)把x=1,f(x)=4带入，得 f'(x)=-5/2 可以求出切线方程为y...
Let f(x)=8x+20/(x^2).Then the equation of the tangent line to the graph of f(x) at the point(2,21) is given by Y=mx+b for m=?b=? 相关知识点: 试题来源: 解析 给出的那个点的坐标(2,21)都是多余的,给其中一个坐标就行了f'(x)=8-40/(x^3)sof'(2)=3,m=3and the ...
1 y = sin(tan 4x)求导;y = x sin(1/x)求导;Find an equation of the tangent line to the curve at the given point. y = sin(sin x), (3π, 0);y = 3x2cosxcotx求导 2y = sin(tan 4x)求导;y = x sin(1/x)求导;Find an equation of the tangent line to the curve at the giv...
Find an equation for the tangent line to the curve x^2y + xy^3 = 2 at the point (1; 1). 扫码下载作业帮搜索答疑一搜即得 答案解析 查看更多优质解析 解答一 举报 题目意思是,求曲线 x^2y + xy^3 = 2在点(1,1)处的切线方程.对方程两边取全导,d(x^2y)+d(xy^3)=2,2xydx+x^2dy+y...
Consider the curve defined by {eq}xcos(y)+4y=4\pi {/eq}. Write the equation of the tangent line to the curve at the point {eq}(0,\pi) {/eq} Tangent to a Curve The slope of a tangent to a curve {eq}\displaystyle y=f(x) {/...