Find an equation of the tangent plane to the parametric surface x= 2r \cos \theta, y=4r \sin \theta, z=r at the point (2 \sqrt{2},4\sqrt{2},2) when r=2, \theta= \pi/4. The answer should be an express Let S be the surfa...
【解析】 S Iution:x+y±2√2=0 . Let the equation of the tangent line be y= -x +b. Substituting this into the equation of the circle: 2x^2- 2bx+b^2-4=0 . Since the line is tangent to the circle, we have △=(-2b)^2-4*2(b^2-4)=0 Solving for b: b =±2 2. So...
题的意思是：求f(x)=8/√(x^2+3x)在点(1,4)处的切线方程 重点是求函数在x=1处的f'(x)直接求导很麻烦，可采用对数求导法，lnf(x)=ln8-(ln(x^2+3x))/2 两边同时对x求导，f'(x)/f(x)=-(2x+3)/2(x^2+3x)把x=1,f(x)=4带入，得 f'(x)=-5/2 可以求出切线方程为y...
求导y'=6(sinx+xcosx)在π/2处y'=6 切线方程y-3π=6(x-π/2)即y=6x
100分求一道数学题,Find an equation for the tangent line to the curve x^2y + xy^3 = 2 at the point (1; 1). 答案 题目意思是,求曲线 x^2y + xy^3 = 2在点(1,1)处的切线方程.对方程两边取全导,d(x^2y)+d(xy^3)=2,2xydx+x^2dy+y^3dx+3xy^2dy=0,整理得 dy/dx=-(2xy+y^...
1一个点最多可以有几条切线?Find the equation of the tangent line to curve (X^2/16)-(y^2/9)=1at point (-5,9/4)..我不会翻译.回答标题的问题或者直接解答这个问题.(x^2)/16 + (Y^2)/9 = 1蝈蝈墨水鱼,我没让你求X和Y啊。是求切线的方程式拉。而且。不是问圆啦。都怪我没讲清楚。
equation of the line tangent 公式我们要找出直线与曲线相切的方程。 首先,我们需要知道切线的定义和性质,然后使用这些性质来找出切线的方程。 假设曲线方程为 y = f(x),切点为 (x0, f(x0))。 切线的斜率等于函数在该点的导数,即 f'(x0)。 所以,切线的方程可以表示为:y - f(x0) = f'(x0) ×...
百度试题 结果1 题目Use implicit differentiation to find an equation of thetangent line to the curve atthe given point.2(x^2+y^2)^2=25(x^2-y^2) (3,1)(lemniscate)y0 相关知识点: 试题来源: 解析 y=-9/(13)x+(40)/(13) 反馈 收藏 ...
Find the equation of line tangent to the graph of f(x)=e+ln x at x=1? 答案 e是常数,f'(x)=1/x,所以切线在x=1点的斜率是1,在x=1点的函数值是e.So the equation of the tangent line of graph at x=1 is f(x)=x+e-1相关推荐 1Find the equation of line tangent to the grap...
Find an equation for the plane tangent at the point (1, 1, 3) to the surface given by the parametric equations x = u^2; y = v^2, z = u + 2v. Find an equation of the tangent plane to the parametric surface...